It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 10³ m³. The decay product of Radon ( Rn ) is 28 Po that will further decay into other nuclei. However, for simplicity, assume that 18 Po is the product you can measure before it further decays. Calculate in grams how much 218 Po (assume the AMU is 218) will be generated after 8 hours of decay? 86 84 84 84 A. 3.61 x 10° g B. 2.55 x 104g C. 3.61 x 104 g D. 8.42 x 103

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It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed
basement with a volume of 2.0 x 10³ m³.
The decay product of Radon ( Rn ) is 28 Po that will further decay into other nuclei. However, for
simplicity, assume that 18 Po is the product you can measure before it further decays. Calculate in
grams how much 218 Po (assume the AMU is 218) will be generated after 8 hours of decay?
86
84
84
84
A. 3.61 x 10° g
B. 2.55 x 104g
C. 3.61 x 104 g
D. 8.42 x 103
Transcribed Image Text:It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 10³ m³. The decay product of Radon ( Rn ) is 28 Po that will further decay into other nuclei. However, for simplicity, assume that 18 Po is the product you can measure before it further decays. Calculate in grams how much 218 Po (assume the AMU is 218) will be generated after 8 hours of decay? 86 84 84 84 A. 3.61 x 10° g B. 2.55 x 104g C. 3.61 x 104 g D. 8.42 x 103
relate to the following scenario: It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d,
atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 103 m3.
Transcribed Image Text:relate to the following scenario: It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 103 m3.
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