It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F. You are not entirely convinced. You believe that it is not 98.6∘F. You collected data using 49 healthy people and found that they had a mean body temperature of 98.24∘F with a standard deviation of 1.05∘F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6∘F.a) Identify the null and alternative hypotheses? H0: H1: b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)?left-tailedright-tailedtwo-tailedc) Identify the appropriate significance level as a decimal.d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places.e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.f) Do you reject the null hypothesis?We reject the null hypothesis, since the p-value is less than the significance level.We reject the null hypothesis, since the p-value is not less than the significance level.We fail to reject the null hypothesis, since the p-value is less than the significance level.We fail to reject the null hypothesis, since the p-value is not less than the significance level.g) Select the statement below that best represents the conclusion that can be made.There is sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthy adult is not 98.6∘F .There is not sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthy adult is not 98.6∘F.The is sufficent evidence to support the claim that the mean body temperature of a healthy adult is not 98.6∘F.There is not sufficient evidence to support the claim that the mean body temperature of a healthy adult is not 98.6∘F. It is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirelyconvinced. You believe that it is not 98.6° F. You collected data using 49 healthy people and found that they hada mean body temperature of 98.24°F with a standard deviation of 1.05° F. Use a 0.05 significance level to testthe claim that the mean body temperature of a healthy adult is not 98.6° F.a) Identify the null and alternative hypotheses?Ho: Select an answer vH1: Select an answerb) What type of hypothesis test should you conduct (left-, right-, or two-tailed)?O left-tailedOright-tailedOtwo-tailedc) Identify the appropriate significance level as a decimal.d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimalplaces.e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.f) Do you reject the null hypothesis?OWe reject the null hypothesis, since the p-value is less than the significance level.OWe reject the null hypothesis, since the p-value is not less than the significance level.OWe fail to reject the null hypothesis, since the p-value is less than the significance level.OWe fail to reject the null hypothesis, since the p-value is not less than the significance level.g) Select the statement below that best represents the conclusion that can be made.O There is sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthyadult is not 98.6°F.There is not sufficient evidence to warrant rejection of the claim that the mean body temperature of ahealthy adult is not 98.6° F.O The is sufficent evidence to support the claim that the mean body temperature of a healthy adult is not98.6° F.O There is not sufficient evidence to support the claim that the mean body temperature of a healthy adult isnot 98.6° F.

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Description: It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F. You are not entirely convinced. You believe that it is not 98.6∘F. You collected data using 49 healthy people and found that they had a mean body temperature of 98.2

Given, Population mean (μ)=98.6 Sample size(n) = 49 Sample mean (x-)=98.24 Standard deviation…

Answered: It is commonly believed that the mean…

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It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F. You are not entirely convinced. You believe that it is not 98.6∘F. You collected data using 49 healthy people and found that they had a mean body temperature of 98.24∘F with a standard deviation of 1.05∘F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6∘F.

a) Identify the null and alternative hypotheses?

H0:

H1:

b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)?

left-tailed
right-tailed
two-tailed

c) Identify the appropriate significance level as a decimal.

d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places.

e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.

f) Do you reject the null hypothesis?

We reject the null hypothesis, since the p-value is less than the significance level.
We reject the null hypothesis, since the p-value is not less than the significance level.
We fail to reject the null hypothesis, since the p-value is less than the significance level.
We fail to reject the null hypothesis, since the p-value is not less than the significance level.

g) Select the statement below that best represents the conclusion that can be made.

There is sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthy adult is not 98.6∘F

.
There is not sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthy adult is not 98.6∘F
.
The is sufficent evidence to support the claim that the mean body temperature of a healthy adult is not 98.6∘F
.
There is not sufficient evidence to support the claim that the mean body temperature of a healthy adult is not 98.6∘F

It is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirely
convinced. You believe that it is not 98.6° F. You collected data using 49 healthy people and found that they had
a mean body temperature of 98.24°F with a standard deviation of 1.05° F. Use a 0.05 significance level to test
the claim that the mean body temperature of a healthy adult is not 98.6° F.
a) Identify the null and alternative hypotheses?
Ho: Select an answer v
H1: Select an answer
b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)?
O left-tailed
Oright-tailed
Otwo-tailed
c) Identify the appropriate significance level as a decimal.
d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal
places.
e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.
f) Do you reject the null hypothesis?
OWe reject the null hypothesis, since the p-value is less than the significance level.
OWe reject the null hypothesis, since the p-value is not less than the significance level.
OWe fail to reject the null hypothesis, since the p-value is less than the significance level.
OWe fail to reject the null hypothesis, since the p-value is not less than the significance level.
g) Select the statement below that best represents the conclusion that can be made.
O There is sufficient evidence to warrant rejection of the claim that the mean body temperature of a healthy
adult is not 98.6°F.
There is not sufficient evidence to warrant rejection of the claim that the mean body temperature of a
healthy adult is not 98.6° F.
O The is sufficent evidence to support the claim that the mean body temperature of a healthy adult is not
98.6° F.
O There is not sufficient evidence to support the claim that the mean body temperature of a healthy adult is
not 98.6° F.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution

Step 1

Given,

Population mean $(μ) = 98.6$

Sample size(n) = 49

Sample mean $(\bar{x}) = 98.24$

Standard deviation (s)=1.05

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