It is claimed that the proportion of high school athletes who go on to play sports in college is 0.10. Believing this claimed value is too high, a researcher gathers data from a random sample of former high school athletes in order to conduct a hypothesis test, and the resulting P-value is 0.02. Which of the following is a correct interpretation of this P-value?
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- It is claimed that the proportion of high school athletes who go on to play sports in college is 0.10. Believing this claimed value is too high, a researcher gathers data from a random sample of former high school athletes in order to conduct a hypothesis test, and the resulting P-value is 0.02. Which of the following is a correct interpretation of this P-value?
- The probability that the null hypothesis is true is 0.02.
- The probability that a randomly chosen high school athlete will go on to play sports in college is 0.02.
- Because the P-value is small, this means we cannot rule out the null hypothesis as a reasonable explanation of the data.
- If we assume to begin with that the null hypothesis is true, the probability of obtaining a sample result as extreme or more extreme than the one observed is 0.02.
- The probability that the null hypothesis is false is 0.02.
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- We learned in Exercise 3.26 that about 90% of American adults had chickenpox before adulthood. We now consider a random sample of 120 American adults. How many people in this sample would you expect to have had chickenpox in their childhood? And with what standard deviation? Would you be surprised if there were 105 people who have had chickenpox in their childhood? What is the probability that 105 or fewer people in this sample have had chickenpox in their childhood? How does this probability relate to your answer to part b?Annie is concerned over a report that "a woman over age 4040 has a better chance of being killed by a terrorist than of getting married." A study found that the likelihood of marriage for a never-previously-wed, 4040-year-old university-educated American woman was 2.8%2.8%. To demonstrate that this percentage is too small, Annie uses her resources at the Baltimore Sun to conduct a simple random sample of 513513 never-previously-wed, university-educated, American women who were single at the beginning of their 4040s and who are now 4545. Of these women, 2323 report now being married. Does this evidence support Annie’s claim, at the 0.050.05 level of significance, that the chances of getting married for this group is greater than 2.8%2.8%? Step 3 of 3 : Draw a conclusion and interpret the decision.A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 35.2 weeks. Assume that for the population of all unemployed individuals the population mean length of unemployment is 35.2 weeks and that the population standard deviation is 5.6 weeks. Suppose you would like to select a random sample of 29 unemployed individuals for a follow-up study. Find the probability that a single randomly selected value is between 33.1 and 33.8. P(33.1 < X < 33.8) = 0.0475 29 is Find the probability that a sample of size n randomly selected with a mean between 33.1 and 33.8. Р(3.1 < М < 33.8) - Enter your answers as numbers accurate to 4 decimal places.
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To put it another way, is the mean number of desks produced different from 200 at the 0.01 significance level? If the VP took a sample of new production, where he took the data for 50 weeks and found the average production to be 203.5 desks, what would you conclude?The starting salaries of financial accountants are positively skewed, with a mean of $52,000 and a standard deviation of $12,000. The starting salaries of cost accountants have a slightly skewed distribution, with a mean of $58,000 and a standard deviation of $14,000. A random sample of 40 financial accountants and a random sample of 50 cost accountants are selected. What is the probability that the starting salaries of the financial accountants will not exceed the starting salaries of A Round the final cost accountants? answer to four decimal places.Two different simple random samples are drawn from two different populations. The first sample consists of 40 people with 20 having a common attribute. The second sample consists of 1800 people with 1291 of them having the same attribute. Compare the results from a hypothesis test p1=p2 (with a 0.05 significance level) and a 95% confidence interval estimate of p1-p2. What are the null and alternative hypotheses for the hypothesis test?The coach of a basketball team thinks the referee is using a weighted coin to decide which team gets the ball. He looks at the last 140 coin tosses and observes that there were 85 heads and 55 tails. Answer the following questions. (1) What is the null hypothesis? The observed frequency is not different than the expected frequency, meaning that the coin is biased The observed frequency is not different than the expected frequency, meaning that the coin is fair. The observed frequency is different than the expected frequency, meaning that the coin is fair. The observed frequency is different than the expected frequency, meaning that the coin is biased. (2) What is the calculated value of chi-square? 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