It is believed that the median yearly income in a suburb of Atlanta is $70,000. A sample of 67 residents was taken. Thirty-eight had yearly incomes above $70,000, 26 had yearly incomes below $70,000, and 3 had yearly incomes equal to $70,000. The null hypothesis to be tested is Ho: Median = $70,000. The mean and the standard deviation (respectively) for this test about the median are O 32 & 16 O 33,5 & 16 O 32 & 4 33.5 & 4
It is believed that the median yearly income in a suburb of Atlanta is $70,000. A sample of 67 residents was taken. Thirty-eight had yearly incomes above $70,000, 26 had yearly incomes below $70,000, and 3 had yearly incomes equal to $70,000. The null hypothesis to be tested is Ho: Median = $70,000. The mean and the standard deviation (respectively) for this test about the median are O 32 & 16 O 33,5 & 16 O 32 & 4 33.5 & 4
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![It is believed that the median yearly income in a suburb of Atlanta is $70,000. A sample of 67 residents was taken. Thirty-eight had yearly incomes above $70,000, 26 had yearly incomes below $70,000, and 3 had yearly incomes equal to $70,000. The null hypothesis to be tested is \( H_0: \text{Median} = \$70,000 \).
The mean and the standard deviation (respectively) for this test about the median are:
- \( \bigcirc \) 32 & 16
- \( \bigcirc \) 33.5 & 16
- \( \bigcirc \) 32 & 4
- \( \bigcirc \) 33.5 & 4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc00f41a8-3019-411c-9841-b4d3b90602dd%2Fd429562d-0540-4c53-964c-bee28b8d8723%2Foado21i_processed.png&w=3840&q=75)
Transcribed Image Text:It is believed that the median yearly income in a suburb of Atlanta is $70,000. A sample of 67 residents was taken. Thirty-eight had yearly incomes above $70,000, 26 had yearly incomes below $70,000, and 3 had yearly incomes equal to $70,000. The null hypothesis to be tested is \( H_0: \text{Median} = \$70,000 \).
The mean and the standard deviation (respectively) for this test about the median are:
- \( \bigcirc \) 32 & 16
- \( \bigcirc \) 33.5 & 16
- \( \bigcirc \) 32 & 4
- \( \bigcirc \) 33.5 & 4
![Sixteen people were given two types of cereal, Brand X and Brand Y. Two people preferred Brand X and thirteen people preferred Brand Y. We want to determine whether or not customers prefer one brand over the other. The null hypothesis that is being tested is
- ○ \( H_0: p = 0.5 \)
- ○ \( H_0: \mu = 0.5 \)
- ○ \( H_0: \mu = 8 \)
- ○ \( H_0: p = 8 \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc00f41a8-3019-411c-9841-b4d3b90602dd%2Fd429562d-0540-4c53-964c-bee28b8d8723%2F5fepyj8_processed.png&w=3840&q=75)
Transcribed Image Text:Sixteen people were given two types of cereal, Brand X and Brand Y. Two people preferred Brand X and thirteen people preferred Brand Y. We want to determine whether or not customers prefer one brand over the other. The null hypothesis that is being tested is
- ○ \( H_0: p = 0.5 \)
- ○ \( H_0: \mu = 0.5 \)
- ○ \( H_0: \mu = 8 \)
- ○ \( H_0: p = 8 \)
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