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It Icav es? 37, Dragsters can actually reach a top speed of 145 m/s in only 4.45 s- 0 and Example 2.11. (a) Calculate the average acceleration for such a dragster. (b) Find the final velocity of tis dragster starting from rest and accelerating at the rate found in (a) for 402 m (a quarter mile) without using any information on time. (c) Why is the final velocity greater than that used to find the average acceleration? Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity. considerably less time than given in Example

It Icav es? 37, Dragsters can actually reach a top speed of 145 m/s in only 4.45 s- 0 and Example 2.11. (a) Calculate the average acceleration for such a dragster. (b) Find the final velocity of tis dragster starting from rest and accelerating at the rate found in (a) for 402 m (a quarter mile) without using any information on time. (c) Why is the final velocity greater than that used to find the average acceleration? Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity. considerably less time than given in Example

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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It Icav es? 37, Dragsters can actually reach a top speed of 145 m/s in only 4.45 s- 0 and Example 2.11. (a) Calculate the average acceleration for such a dragster. (b) Find the final velocity of tis dragster starting from rest and accelerating at the rate found in (a) for 402 m (a quarter mile) without using any information on time. (c) Why is the final velocity greater than that used to find the average acceleration? Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity. considerably less time than given in Example
Transcribed Image Text:It Icav es? 37, Dragsters can actually reach a top speed of 145 m/s in only 4.45 s- 0 and Example 2.11. (a) Calculate the average acceleration for such a dragster. (b) Find the final velocity of tis dragster starting from rest and accelerating at the rate found in (a) for 402 m (a quarter mile) without using any information on time. (c) Why is the final velocity greater than that used to find the average acceleration? Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity. considerably less time than given in Example
Expert Solution
Step 1

The given information on the dragster is that they can reach a top speed of 145 m/s in a short time of 4.45 seconds, starting from rest.

Thus the dragsters must be producing large amounts of accelerations with their drag cars to reach such a high velocities in such short times.

Average acceleration over a period of time is defined as the change in velocity over that same period of time.

For the given problem, since the dragster starts from rest, so its initial velocity=0.

The dragster achieves a velocity of 145 m/s in 4.45 seconds. So the average acceleration over this period of time is

a=145-04.45a=1454.45a=32.58 m/s2

This is the required average acceleration of the dragster

 

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