It can be shown that Jo has infinitely many zeros for x > 0. In particular, the first three zeros are approximately 2.405, 5.520, and 8.653 (see Figure 5.7.1). Let A;, j = 1, 2, 3, ..., denote the zeros of Jo; it follows that x = 0, 1, Jo(A;æ) = x = 1. Verify that y = Jo(A;x) satisfies the differential equation 1 y" + y' + X3y = 0, x > 0.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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It can be shown that Jo has infinitely many zeros for r > 0. In particular, the first three
zeros are approximately 2.405, 5.520, and 8.653 (see Figure 5.7.1). Let A;, j = 1, 2, 3, ...,
denote the zeros of Jo; it follows that
[1, x = 0,
Jo(A;a) =
0, х3D 1.
Verify that y = Jo(Ajx) satisfies the differential equation
1
y" + y' + X}y = 0,
x > 0.
Transcribed Image Text:It can be shown that Jo has infinitely many zeros for r > 0. In particular, the first three zeros are approximately 2.405, 5.520, and 8.653 (see Figure 5.7.1). Let A;, j = 1, 2, 3, ..., denote the zeros of Jo; it follows that [1, x = 0, Jo(A;a) = 0, х3D 1. Verify that y = Jo(Ajx) satisfies the differential equation 1 y" + y' + X}y = 0, x > 0.
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