It A is an invertible nxn matrix, then the inverse of matrixA IS A A3D det A adj A and ad - bc+ 0, then Ais invertible and the inverse is c d 1 d -b Show that if A is 2x2, then the first theorem gives the same formula for A-1 as that given by the second theorem. ad - bc - C a What must be done to prove the theorems are equivalent? O A. Evaluate the determinant of matrix A = d -b using A 1 adj A det A a O B. Evaluate the inverse of matrix A = a b using A %3D c d det A adj A OC. Evaluate the determinant of matrix A = | a b 1 d -b using A %3D c d ad - bc a O D. Evaluate the inverse of matrix A= d -b using A 1 adj A. det A

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