istance of magnitude directed oPposite to the velocity, 1325 the velocity v is measured in m/s. Use g=9.8 m/s² as the acceleration due to gravity. Round your answers to 2 decimal places. d the maximum height above the ground that the ball reaches. ght: m d the time that the ball hits the ground. seconds ne: a graphing utility to plot the graphs of velocity and position sus time.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

a. 48.562m
b. 5.194s

that is the correct answer to that question, what we need is the solution. 

0,15
kg is thrown upward with initial velocity 20 m/s
A ball with mass
from the roof of a building 30m high. Assume there is a force due to
air resistance of magnitude
directed opposite to the velocity,
1325
where the velocity v is measured in m/s.
NOTE: Use g=9.8 m/s as the acceleration due to gravity.
Round your answers to 2 decimal places.
a) Find the maximum height above the ground that the ball reaches.
Height:
m
b) Find the time that the ball hits the ground.
Time:
seconds
c) Use a graphing utility to plot the graphs of velocity and position
versus time.
Transcribed Image Text:0,15 kg is thrown upward with initial velocity 20 m/s A ball with mass from the roof of a building 30m high. Assume there is a force due to air resistance of magnitude directed opposite to the velocity, 1325 where the velocity v is measured in m/s. NOTE: Use g=9.8 m/s as the acceleration due to gravity. Round your answers to 2 decimal places. a) Find the maximum height above the ground that the ball reaches. Height: m b) Find the time that the ball hits the ground. Time: seconds c) Use a graphing utility to plot the graphs of velocity and position versus time.
V Answer
18. а. 48.562 m
b. 5.194 S
Transcribed Image Text:V Answer 18. а. 48.562 m b. 5.194 S
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