Isotherm Adiabat V (em) O 1000 2000 3000 2 mol of nitrogen gas follow the two proce ow much heat is required for isothermal pr | kJ ow much heat is required for adiabatic pro kJ Data: R= 8.31 J.mol".K', po = 101.3 kPa

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Chapter1: Units, Trigonometry. And Vectors
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P (atm)
3
Isotherm
Adiabat
V (em)
1000 2000 3000
0.102 mol of nitrogen gas follow the two processes shown in the figure.
a. How much heat is required for isothermal process?
kJ
b. How much heat is required for adiabatic process?
kJ
Data: R= 8.31 J.mol1.K', po = 101.3 kPa
Nitrogen: C, = 20.8 J.mol1.K1; Cp = 29.1 J.mol1.K1
Water: c = 4190 J.kg1.K'; C = 75.4 J.mol1.K1
Transcribed Image Text:P (atm) 3 Isotherm Adiabat V (em) 1000 2000 3000 0.102 mol of nitrogen gas follow the two processes shown in the figure. a. How much heat is required for isothermal process? kJ b. How much heat is required for adiabatic process? kJ Data: R= 8.31 J.mol1.K', po = 101.3 kPa Nitrogen: C, = 20.8 J.mol1.K1; Cp = 29.1 J.mol1.K1 Water: c = 4190 J.kg1.K'; C = 75.4 J.mol1.K1
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