Isoamyl acetate: Put in the molecular formula of the ions responsible for peaks at 59 (involving O) and 71. Use the following order: C, H, O and include a '+' at the end. A formatting example for mass of 44 would be C2H4O+ L00 - MS-NU-0039 80 - 60 - 40 - 20 - M.I. 25 50 75 100 125
Isoamyl acetate: Put in the molecular formula of the ions responsible for peaks at 59 (involving O) and 71. Use the following order: C, H, O and include a '+' at the end. A formatting example for mass of 44 would be C2H4O+ L00 - MS-NU-0039 80 - 60 - 40 - 20 - M.I. 25 50 75 100 125
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Title: Understanding Isoamyl Acetate Molecular Ion Peaks**
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**Text:**
Isoamyl acetate: Put in the molecular formula of the ions responsible for peaks at 59 (involving O) and 71. Use the following order: C, H, O and include a '+' at the end. A formatting example for mass of 44 would be C2H4O+.
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**Graph Explanation:**
The graph displayed is a mass spectrum for isoamyl acetate. The x-axis represents the mass-to-charge ratio (m/z), and the y-axis shows the relative intensity of the ion signals.
- The peak at m/z 59 corresponds to the ion with the molecular formula C3H3O2+.
- The peak at m/z 71 corresponds to the ion with the molecular formula C5H11+.
The most intense peak is marked as "M.I."
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This information is vital for understanding the fragmentation pattern of isoamyl acetate, which can be used in identifying and studying its structure in mass spectrometry.
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