Ise a system of linear equations in three variables to solve the following problem. at a college production of a play, 350 tickets were sold. The ticket prices were $8, S10, and $12, and the total income from ticket sales was $3180. How ma f each type were sold if the combined number of $8 and $10 tickets sold was 6 times the number of $12 tickets sold? Vrite a system of linear equations using the given information. Choose correct answer below. x+y+z=3180 x+y+z= 3180 DA. 8x + 10y + 12z = 350 OB. 8x + 10y + 12z = 350 x+y + 6z = 0 |x+y - 6z = 0 x+y+z= 350 x+y+z= 350 8x + 10y + 12z = 3180 OD. 8x + 10y + 12z = 3180 x+y+ 6z = 0 x+y - 6z = 0 There were tickets of $8, tickets of $10, and tickets of $12 sold.

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Use a system of linear equations in three variables to solve the following problem.
At a college production of a play, 350 tickets were sold. The ticket prices were $8, S10, and $12, and the total income from ticket sales was $3180. How many tickets
of each type were sold if the combined number of $8 and $10 tickets sold was 6 times the number of $12 tickets sold?
Write a system of linear equations using the given information. Choose correct answer below.
x+y+z= 3180
x+y +z= 3180
O A.
8x + 10y + 12z = 350
OB.
8x + 10y + 12z = 350
x+y + 6z = 0
x+y - 6z = 0
x+y+z= 350
x+y+z= 350
OC.
8x + 10y + 12z = 3180
OD.
8x + 10y + 12z = 3180
x+y + 6z = 0
x+y- 6z = 0
There were
tickets of $8,
tickets of $10, and tickets of $12 sold.
Transcribed Image Text:Use a system of linear equations in three variables to solve the following problem. At a college production of a play, 350 tickets were sold. The ticket prices were $8, S10, and $12, and the total income from ticket sales was $3180. How many tickets of each type were sold if the combined number of $8 and $10 tickets sold was 6 times the number of $12 tickets sold? Write a system of linear equations using the given information. Choose correct answer below. x+y+z= 3180 x+y +z= 3180 O A. 8x + 10y + 12z = 350 OB. 8x + 10y + 12z = 350 x+y + 6z = 0 x+y - 6z = 0 x+y+z= 350 x+y+z= 350 OC. 8x + 10y + 12z = 3180 OD. 8x + 10y + 12z = 3180 x+y + 6z = 0 x+y- 6z = 0 There were tickets of $8, tickets of $10, and tickets of $12 sold.
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