Is W a subspace of the vector space? If not, state why. (Select all that apply.) W is the set of all vectors in R2 whose components are rational numbers. O w is a subspace of R2. O w is not a subspace of R2 because it is not closed under addition. O wis not a subspace of R2 because it is not closed under scalar multiplication.

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Chapter2: Second-order Linear Odes
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**Is \( W \) a Subspace of the Vector Space?**

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*Question:*

Is \( W \) a subspace of the vector space? If not, state why. (Select all that apply.)

*Information Given:*

\( W \) is the set of all vectors in \( \mathbb{R}^2 \)  whose components are rational numbers.

*Options:*

- [ ] \( W \) is a subspace of \( \mathbb{R}^2 \).
- [ ] \( W \) is not a subspace of \( \mathbb{R}^2 \) because it is not closed under addition.
- [ ] \( W \) is not a subspace of \( \mathbb{R}^2 \) because it is not closed under scalar multiplication.

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*Explanation:*

To determine if \( W \) is a subspace, we need to verify if it satisfies the conditions for a subspace. Specifically, we need to check if \( W \) is closed under addition and scalar multiplication. If \( W \) fails any of these conditions, it is not a subspace.
Transcribed Image Text:**Is \( W \) a Subspace of the Vector Space?** --- *Question:* Is \( W \) a subspace of the vector space? If not, state why. (Select all that apply.) *Information Given:* \( W \) is the set of all vectors in \( \mathbb{R}^2 \) whose components are rational numbers. *Options:* - [ ] \( W \) is a subspace of \( \mathbb{R}^2 \). - [ ] \( W \) is not a subspace of \( \mathbb{R}^2 \) because it is not closed under addition. - [ ] \( W \) is not a subspace of \( \mathbb{R}^2 \) because it is not closed under scalar multiplication. --- *Explanation:* To determine if \( W \) is a subspace, we need to verify if it satisfies the conditions for a subspace. Specifically, we need to check if \( W \) is closed under addition and scalar multiplication. If \( W \) fails any of these conditions, it is not a subspace.
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