Is v= 1321 - 2 an eigenvector of A = -4 3 3 2 - 3 - 1 -2? If so, find the eigenvalue. 0 - 2 Select the correct choice below and, if necessary, fill in the answer box within your choice. O A. Yes, v is an eigenvector of A. The eigenvalue is λ = B. No, v is not an eigenvector of A.
Is v= 1321 - 2 an eigenvector of A = -4 3 3 2 - 3 - 1 -2? If so, find the eigenvalue. 0 - 2 Select the correct choice below and, if necessary, fill in the answer box within your choice. O A. Yes, v is an eigenvector of A. The eigenvalue is λ = B. No, v is not an eigenvector of A.
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.4: The Singular Value Decomposition
Problem 26EQ
Related questions
Question
![Is v=
1231
-
an eigenvector of A =
-4 3 3
2 - 3
- 1
-2? If so, find the eigenvalue.
0 - 2
Select the correct choice below and, if necessary, fill in the answer box within your choice.
O A. Yes, v is an eigenvector of A. The eigenvalue is λ =
B. No, v is not an eigenvector of A.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a6c3af6-91f1-478b-99db-a0b0fd9518f2%2F84c9a8d6-e994-428a-adc7-51684db27f1c%2Fry0jfri_processed.png&w=3840&q=75)
Transcribed Image Text:Is v=
1231
-
an eigenvector of A =
-4 3 3
2 - 3
- 1
-2? If so, find the eigenvalue.
0 - 2
Select the correct choice below and, if necessary, fill in the answer box within your choice.
O A. Yes, v is an eigenvector of A. The eigenvalue is λ =
B. No, v is not an eigenvector of A.
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