Is v= 1321 - 2 an eigenvector of A = -4 3 3 2 - 3 - 1 -2? If so, find the eigenvalue. 0 - 2 Select the correct choice below and, if necessary, fill in the answer box within your choice. O A. Yes, v is an eigenvector of A. The eigenvalue is λ = B. No, v is not an eigenvector of A.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Problem Statement:**

Is \(\mathbf{v} = \begin{bmatrix} 3 \\ -2 \\ 1 \end{bmatrix}\) an eigenvector of \(A = \begin{bmatrix} -4 & 3 & 3 \\ 2 & -3 & -2 \\ -1 & 0 & -2 \end{bmatrix}\)? If so, find the eigenvalue.

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**Select the correct choice below and, if necessary, fill in the answer box within your choice:**

- **A.** Yes, \(\mathbf{v}\) is an eigenvector of \(A\). The eigenvalue is \(\lambda =\) \(\boxed{\phantom{\lambda}}\).

- **B.** No, \(\mathbf{v}\) is not an eigenvector of \(A\).
Transcribed Image Text:**Problem Statement:** Is \(\mathbf{v} = \begin{bmatrix} 3 \\ -2 \\ 1 \end{bmatrix}\) an eigenvector of \(A = \begin{bmatrix} -4 & 3 & 3 \\ 2 & -3 & -2 \\ -1 & 0 & -2 \end{bmatrix}\)? If so, find the eigenvalue. --- **Select the correct choice below and, if necessary, fill in the answer box within your choice:** - **A.** Yes, \(\mathbf{v}\) is an eigenvector of \(A\). The eigenvalue is \(\lambda =\) \(\boxed{\phantom{\lambda}}\). - **B.** No, \(\mathbf{v}\) is not an eigenvector of \(A\).
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