2.1Is there evidence of a difference in mean wear among the four treatments? Use a= 0.05.[HINT: Total SS = 97.0319 and SST = 36.7497]Estimate the mean difference in "haze" increase between treatments B and D, using a 99%confidence interval. Interpret your finding2.2 2.QUESTIONIt has been hypothesized that treatments of plastic used in optic lenses will improve wear. Fourdifferent treatments are to be tested. To determine whether any differences in mean wear existamong treatments, 28 castings from a single formulation of the plastic were made and 7 castingswere randomly assigned to each of the treatments. Wear was determined by measuring theincrease in "haze" after 200 cycles of abrasion (better wear being indicated by smaller increases).The data collected are reported in the accompanying table.TreatmentAB9.1611.9511.4711.3513.2915.159.548.7312.0714.7511.2610.0011.9714.7913.669.7513.3115.4811.1811.7112.3213.4715.0312.4511.7813.0614.8612.3883.9098.6587.0076.3711.98614.09312.42910.910

In this problem, we have four treatments A, B, C and D . Let us denote the true means of 4…

Answered: Is there evidence of a difference in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher would like to know how much physical endurance is affected by a common herbal supplement. The researcher measures endurance for a sample of n = 9 participants. Each is then given a 30-day supply of the herbs and, one month later, endurance is measured again. For this sample, endurance increased by an average of MD= 6 points with SSD = 216. a. make a point estimate of the mean difference in endurance after taking the herbs. b. make a 95% confidence interval estimate of the population mean difference.
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Is there evidence of a difference in mean wear among the four treatments? Use a= 0.05. [HINT: Total SS 97.0319 and SST = 36.7497] 2.1 Estimate the mean difference in "haze" increase between treatments B and D, using a 99% confidence interval. Interpret your finding 2.2