Is there a doctor in the house? A market research firm reported the mean annual earnings of all family practitioners in the United States was $178,258 . A random sample of 59 family practitioners in Los Angeles had mean earnings of x $191,350 with a standard deviation of $42,897. Do the data provide sufficient evidence to conclude that the mean salary for family practitioners in Los Angeles differs from the national average? Use the a= 0.01 level of significance and the critical value method with the table. (a) State the appropriate null and alternate hypotheses. (b) Compute the value of the test statistic. (c) State a conclusion. Use the a=0.01 level of significance.

Is there a doctor in the house? A market research firm reported the mean annual earnings of all family practitioners in the United States was $178,258 . A random sample of 59 family practitioners in Los Angeles had mean earnings of x $191,350 with a standard deviation of $42,897. Do the data provide sufficient evidence to conclude that the mean salary for family practitioners in Los Angeles differs from the national average? Use the a= 0.01 level of significance and the critical value method with the table. (a) State the appropriate null and alternate hypotheses. (b) Compute the value of the test statistic. (c) State a conclusion. Use the a=0.01 level of significance.

Name: Is there a doctor in the house? A market research firm reported the m
Uploaded: 2024-03-20T07:06:16.000Z
Channel: Bartleby
Description: Is there a doctor in the house? A market research firm reported the mean annual earnings of allfamily practitioners in the United States was $178,258 . A random sample of 59 family practitioners inLos Angeles had mean earnings of x $191,350 with a s

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: What percentage of fire station response times are under 3 minutes

A: Let X denote the response times for fire departments. Given that X follows N(mean = 4.5, SD = 1.2),…

Q: Listed below are the lead concentrations in pg/g measured in different traditional medicines. Use a…

A: Note- Since you have posted multiple questions, as per our guidelines we are supposed to answer only…

Q: two classes, one with 18 students and one with 21 students, took an assesment and obtained an…

A: The overall mean is, x̄ = 55.0.The number of students in class 1 is, n1= 18.The mean score of the…

Q: Researchers conducting a study of 15 children with a diagnosis of ADHD wish to assess whether the…

A: The BMI of 15 children is given.

Q: Medical research suggests that systolic blood pressure in adults is approximately normally…

A: Denote X as the blood pressure in adults. It is given that X is approximately normally distributed,…

Q: 0 mg/dL H₁: #0 mg/dL OA. Ho: OC. Ho: μ = 0 mg/dL H₁: >0 mg/dL Determine the test statistic. (Round…

Q: Response time is an important statistic for measuring the effectiveness of a fire department, and is…

A: Using stardization of Normal distribution

Q: In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with…

A: (1). Null and alternate hypotheses: The investigator is specifically interested to test whether the…

Q: Is there a doctor in the house? A market research firm reported the mean annual earnings of all…

A: Hypothesized mean μ = $178,258Sample size (n) = 54Mean x¯ = $192,780Standard deviation (s) =…

Q: Do the data support your claim at the 1% level?

A: The summary of the statistics is, The type of test is right tailed test

Q: The cost of repairing a smart phone that is out of warranty follows a normal distribution with a…

A: Given that, The cost of repairing a smart phone that is out of warranty follows a normal…

Q: A researcher collected data from Boston police officers and found that on average they spent 14.3…

A: From the provided information, Mean (µ) = 14.3 Standard deviation (σ) = 3.2

Q: A market research firm reported that the mean annual earnings of all family practitioners in the…

Q: Do people who exercise regularly have a cholesterol level less than the recommended level of 140? A…

A: The summary of statistics is,

Q: If the heights of intramural college basketball players are normally distributed with mean u =…

A: Given,μ=70σ=6.5P(63.5<X<76.5)=?

Q: The mean height of students in Negron’s Fall statistics classes is 65.6 inches with a standard…

A: Let random variable X be the height of students(in inches).X has normal distribution with…

Q: For 100 randomly selected adults, compute the mean and standard deviation?

A: A recent poll found that 47% of adults believe that the overall state of moral values is poor.Here…

Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw…

A: Given Information: Sample size (n) = 36 Sample mean (x¯) = 0.7 Standard deviation (s) = 1.95…

Q: Suppose the annual employer 401K cost per participant is normally distributed with a mean of $770.…

A: Let X be the random variable representing the cost per participant. Then, X~N(μ,σ2),where…

Q: Response time is an important statistic for measuring the effectiveness of a fire department, and is…

A: Given data,Mean μ=4.5sd σ=1.2P(4<X<6)=?

Q: What percentage of computer programmer major received a starting offer between $32000 and $38000?…

A: The following information has been provided: \mu = 39269, \text{ } \sigma = 2550Mean : μ=39269,…

Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw…

A: Given information: Number of subjects used for test of the effectiveness of garlic n=36 The mean of…

Q: shoppers at the mall spend the same amount of money on average the day after Thanksgiving compared…

A: Given that Sample sizes n1=56 , n2=43 Sample means X̄1= 145 , X̄2=123 , ?1 =46…

Q: The commute tỉme for Cypress College students who drive from their home to the college follows a…

A: Here, µ = 26 and σ = 8.

Q: During a quality assurance check, the actual contents (in grams) of six containers of protein powder…

A: Given: n = 6 Formula Used: Mean = ∑Xin Median = 2(n+1)4thterm

Q: When a distribution is bell-shaped, approximately what percentage of data values fall within 1…

A: We know that, the empirical rule which is also known as 68-95-99.7 rule. The Empirical Rule finds…

Q: Response time is an important statistic for measuring the effectiveness of a fire department, and is…

A: Given X is normal Distributed with mean µ = 4.5 and standard deviation σ = 1.2 now will using…

Q: measure of variability?

A: We know that Mean and Median is used to measure of Central tendency of the given sample data .…

Q: It is known that average house prices today is $371,040 higher compared to 10 years ago and median…

A: Given that: Current 10 years ago Mean 892.44 521.4 Median 900 518 Mode 816 516 Q1 816…

Q: The average wage for bank managers in a certain city is $91,900 per hour with a standard deviation…

A: Given that X~N( μ = 91900 , ? = 24300) μ = 91900 , ? = 24300 Z-score =( x - μ )/?

Q: An article in the San Jose Mercury News stated that students in the California state university…

A: State the hypotheses.

Concept explainers

Inverse Normal Distribution

The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.

Mean, Median, Mode

It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.

Z-Scores

A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.

Topic Video

Question

100%

Is there a doctor in the house? A market research firm reported the mean annual earnings of all
family practitioners in the United States was $178,258 . A random sample of 59 family practitioners in
Los Angeles had mean earnings of x $191,350 with a standard deviation of $42,897 . Do the data
provide sufficient evidence to conclude that the mean salary for family practitioners in Los Angeles
differs from the national average? Use the a=0.01 level of significance and the critical value method
with the table.
(a) State the appropriate null and alternate hypotheses.
(b) Compute the value of the test statistic.
alo
(c) State a conclusion. Use the a=0.01 level of significance.
Part 1 of 5
(a) State the appropriate null and alternate hypotheses.
Ho: H= 178,258
H1: H 178,258
This hypothesis test is a two-tailed
V test.
Part 2 of 5
Find the critical value(s). Round the answer(s) to three decimal places. If there is more than one
critical value, separate them with commas.
Critical value(s): ±2.663
Part: 2 /5
Part 3 of 5
(b) Compute the value of the test statistic. Round the answer to three decimal places.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 12 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Centre, Spread, and Shape of a Distribution$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.4 and a standard deviation of 23.9. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? Ο Α. Ho: μ=0 mg/ldL H1: µ > 0 mg/dL B. Ho : μ=0 mg/dL H1: µ0 mg/dL H1: µ<0 mg/dL D. Ho: µ=0 mg/dL H1:µ#0 mg/dL
An analyst found that the average amount of money in bank accounts at his/her bank is $2,000 with a standard deviation of $150. What would be the variance?
ryan has collected data on individual income (reported in dollars) and has not found any outliers. ryan wants to calculate the average income in his data. which measure of central tendency should he use? -mean -variance -mode -median
During a quality assurance check, the actual contents (in grams) of six containers of protein powder were recorded as 1527, 1532, 1504, 1517, 1528, and 1516. (a) Find the mean and the median of the contents. (b) The third value was incorrectly measured and is actually 1520. Find the mean and the median of the contents again. (c) Which measure of central tendency, the mean or the median, was affected more by the data entry error? ..... (a) The mean is (Round to one decimal place as needed.) The median is (Type an integer or a decimal. Do not round.) (b) The mean is (Round to one decimal place as needed.) The median is (Type an integer or a decimal. Do not round.) (c) After correcting the error, the mean by and the median by The was affected more. (Round to one decimal place as needed.)
A newspaper article reports that the mean cost for preventative dental care per year is $175 with a standard deviation of $35 (assume that this is the population standard deviation). You want to test whether the mean cost for preventative dental care in your company is different from what was reported in the article. You take a random sample of 250 employees and find the mean cost is $171. Does this signficantly differ from what was reported in the article? Run the appropriate test at α=0.05. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUST show your work to receive full credit. Partial credit is available.
The admission committee of AUCA passes 33% of those who took the exam. If the scores follow a normal distribution with a mean of 85 and a standard deviation of 9, what is the passing score?
In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.2 and a standard deviation of 1.76. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?
In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.2 and a standard deviation of 17.2. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? Ο Α. Hρ: μ=0 mg/dL O B. Ho: µ=0 mg/dL H;: u#0 mg/dL H,: µ>0 mg/dL O C . H: μ=0 mg/dL O D. Ho: µ>0 mg/dL H;: µ<0 mg/dL H,:µ<0 mg/dL Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value, (Round to three decimal…
In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.6 and a standard deviation of 1.92. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?
A survey found that the mean commute time is 25.4 minutes for the fifteen largest U.S. cities.The Austin, TX, chamber of commerce feels that Austin's commute time is less. A survey of 25 randomly selected commuters had a mean of 22.1 minutes with a standard deviation of 5.3minutes. At the 10% level, does the survey data suggest that Austin commute time is significantly less than the national average?Your answer should have the following: 1). Significance Level: Alpha =2). Sample Size: n = 3). Sample X =
During a quality assurance check, the actual contents (in grams) of six containers of protein powder were recorded as 1524, 1526, 1499, 1512, 1532, and 1514. (a) Find the mean and the median of the contents. (b) The third value was incorrectly measured and is actually 1518. Find the mean and the median of the contents again. (c) Which measure of central tendency, the mean or the median, was affected more by the data entry error? (a) The mean is 1517.8. (Round to one decimal place as needed.) The median is 1519 (Type an integer or a decimal. Do not round.) (b) The mean is 1521 (Round to one decimal place as needed.) The median is 1521 (Type an integer or a decimal. Do not round.) (c) After correcting the error, the mean affected more. (Round to one decimal place as needed.) by and the median by The was