Is the set of all polynomials p(t) in P, such that p(0) = 1 a subspace of Pn for all integers n ≥ 0. O Yes, it is a subspace of Pn for any integer n > 0. No, it is not a subspace of Pn for any integer n > 0.

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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Polynomial Subspace Question

**Question:**

Is the set of all polynomials \( p(t) \) in \( \mathbb{P}_n \) such that \( p(0) = 1 \) a subspace of \( \mathbb{P}_n \) for all integers \( n \geq 0 \)?

**Options:**

- \( \circ \) Yes, it is a subspace of \( \mathbb{P}_n \) for any integer \( n \geq 0 \).

- \( \circ \) No, it is not a subspace of \( \mathbb{P}_n \) for any integer \( n \geq 0 \).
Transcribed Image Text:### Polynomial Subspace Question **Question:** Is the set of all polynomials \( p(t) \) in \( \mathbb{P}_n \) such that \( p(0) = 1 \) a subspace of \( \mathbb{P}_n \) for all integers \( n \geq 0 \)? **Options:** - \( \circ \) Yes, it is a subspace of \( \mathbb{P}_n \) for any integer \( n \geq 0 \). - \( \circ \) No, it is not a subspace of \( \mathbb{P}_n \) for any integer \( n \geq 0 \).
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