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Is the Moon's motion around the Earth one-dimensional? Explain
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We will use differential equations to model the orbits and locations of Earth, Mars, and the spacecraft using Newton’s two laws mentioned above. Newton’s second law of motion in vector form is: F^→=ma^→ (1) where F^→ is the force vector in N (Newtons), and a^→ is the acceleration vector in m/s^2,and m is the mass in kg. Newton’s law of gravitation in vector form is: F^→=GMm/lr^→l*r^→/lr^→l where G=6.67x10^-11 m^3/s^2*kg is the universal gravitational constant, M is the mass of the larger object (the Sun), and is 2x10^30 kg, and m is the mass the smaller one (the planets or the spacecraft). The vector r^→ is the vector connecting the Sun to the orbiting objects. Step one ) The motion force in Equation(1), and the gravitational force in Equation(2) are equal. Equate the right hand sides of equations (1) and (2), and cancel the common factor on the left and right sides. Answer: f^→=ma^→ f=Gmm/lr^→l^2 a^→=Gmm/lr^→l^2 x r^→/lr^→l r^→=r^→/lr^→l * Gmm Could you please…
The moon's period of revolution around the Earth is 27.3 d. How far away is the moon from the surface of the Earth? O A) 1.33× 107 m B) 3.83 × 108 m C) 3.77 × 108 m D) 4.88 × 10⁹ m
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According to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 × 10° km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). How can the mass of the Earth be calculated using the information above? Select the correct statements. Select one or more: O a. Use Newton's third law. O b. Use Newton's first law. c. Use Coulombs law. O d. Use Newton's second law.
Leave the moon's amplitude (semi-major axis) constant. How does the changing of the moon's orbital period change the calculated value of the planet's mass? a. Increasing the orbital period results in a higher calculated value for the mass of the planet. Decreasing the orbital period results in a lower calculated value for the mass of the planet. b. Increasing the orbital period results in a lower calculated value for the mass of the planet. Decreasing the orbital period results in a higher calculated value for the mass of the planet. c. Increasing the orbital period results in a higher calculates value for the mass of the planet. Decreasing the orbital period results in a higher calculated value for the mass of the planet.
You are planning a dream vacation to Mars. For the orbital dynamics part of the vacation planning assume that Earth is in a circular orbit 1.00 AU from the Sun and Mars is in a circular orbit 1.52 AU from the Sun. Assume the the orbits of Earth and Mars are coplanar and that they go around the Sun the same way. The orbit you plan to use for your trip is an ellipse with the Sun at one focus (Kepler's 1st Law). The perihelion of the ellipse is at Earth's orbit at 1.00 AU and the aphelion is at Mars' orbit at 1.52 AU. Your spacecraft will go around the Sun in the same sense as Earth and Mars. The orbit you have chosen is called a Hohmann Transfer Orbit. A. What is the semi-major axis a of the spacecraft's orbit? What is the eccentricity of the spacecraft's orbit? B. What is the orbital period of the spacecraft? How long does it take to get to Mars? How long does it take to get back? C. When (at what Earth - Mars configuration) do you launch to go? In other words, where does Mars need to…
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