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Is the angle theta equal to the angle that the incline makes with the horizontal line? Why? How was theta solved? What does the symbol theta stand for? When and why was the coefficient of kinetic friction used?

Is the angle theta equal to the angle that the incline makes with the horizontal line? Why? How was theta solved? What does the symbol theta stand for? When and why was the coefficient of kinetic friction used?

International Edition---engineering Mechanics: Statics, 4th Edition
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.3P: Two identical chairs, each weighing 14 lb, are stacked as shown. The center of gravity of each chair...
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Is the angle theta equal to the angle that the incline makes with the horizontal line? Why?

How was theta solved?

What does the symbol theta stand for?

When and why was the coefficient of kinetic friction used?

a. Force P to Start Block Moving Up 800 N P = (800 N) tan 44.29° P = 780 N z tan g, = 4, = 0.35 800 N 0 = 19.29° 25° + 19.29° = 44.29°- R R 25 b. Force P to Keep Block Moving Up 800 N tan g = HK P = (800 N) tan 39.04° P = 649 N z 800 N = 0.25 O = 14.04° R %3D 25° + 14.04° = 39.04°- R 25° c. Force P to Prevent Block from Sliding Down 800 N Ø = 19.29° 25° - 19.29° = 5.71 P = (800 N) tan 5.71° P = 80.0 N z 800 N R 25 R
Transcribed Image Text:a. Force P to Start Block Moving Up 800 N P = (800 N) tan 44.29° P = 780 N z tan g, = 4, = 0.35 800 N 0 = 19.29° 25° + 19.29° = 44.29°- R R 25 b. Force P to Keep Block Moving Up 800 N tan g = HK P = (800 N) tan 39.04° P = 649 N z 800 N = 0.25 O = 14.04° R %3D 25° + 14.04° = 39.04°- R 25° c. Force P to Prevent Block from Sliding Down 800 N Ø = 19.29° 25° - 19.29° = 5.71 P = (800 N) tan 5.71° P = 80.0 N z 800 N R 25 R
SAMPLE PROBLEM 8.2 25° A support block is acted upon by two forces as shown. Knowing that the coefficients of friction between the block and the incline are m, = 0.35 and m = 0.25, determine the force P required (a) to start the block moving up the incline, (b) to keep it moving up, (c) to prevent it from sliding down. 800 N
Transcribed Image Text:SAMPLE PROBLEM 8.2 25° A support block is acted upon by two forces as shown. Knowing that the coefficients of friction between the block and the incline are m, = 0.35 and m = 0.25, determine the force P required (a) to start the block moving up the incline, (b) to keep it moving up, (c) to prevent it from sliding down. 800 N
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