IsR{t = 0C+VCRC Forced Response Problem:Find the value of vc (0)Find the value of ve at t = 0.0013Find the circuit's time constant for t>0The given are as follows: Is=1mA, R=1.2KM, C=1µF, and vc(0-)=3V, and the switch changes position at t=0.a.b.C.d. How long will have to elapse after switching for vcto get to within 1% of its final value? (In terms ofthe number of time constants)e.Give the new value for the capacitance such that thevoltage v reaches its final value in half the originaltime.

As per the guidelines of Bartleby we supposed to answer first three subpart only for solution of…

Answered: Is R{ t = 0 C + VC RC Forced Response…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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I am trying to model a simple RC circuit with one resistor and one capacitor using Simulink. I was given this equation G(jw)=1/(1+jw*tau), tau=RC, and need to convert it to this form in the image: v_dot_o = 1/RC(Vi-Vo). I have also attached a longer image with more detailed steps of how to get to the final equation, but I don't get how a derivative of Vo has appeared out of nowhere somewhere in the middle of the procedure. Please show as many steps as possible and explain the steps if necessary. I'm purely intending to learn from the process, so it'd be really nice if you could explain how each step was done!
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After being closed for a long time the switch in the RC circuit shown below opens at timet=18 ms. Find iO(t) for t > 0 ms. For full credit include the equations and a plot describing iO(t).Hint: use superposition to find the contributions of each source.
Find the convolution using table method I A) Kn) = 8(n) – 8(n-2), B) h(n) = ()" (u(n) – u(n – 4)
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Charging Capacitor: For a charging capacitor the Kirchoff's Loop Rule gives R E – IR C ww C In this case the current is entering the positive plate so I = dQ/dt = CdAVc/dt and we get dVc E – RC - Vc = 0 dt The solution to the differential equation is V.(t) = E (1 – e-t/(RC)) (charging capacitor) Notice that V.(0) = 0 and V.(0) = E as we expect for a charging capacitor. 5. You can easily find the time constant if you are given a graph of voltage across a charging capacitor as a function of time. Whent = RC, the voltage across the capacitor is V.(t = RC) = E(1 – e-1) × 0.63 E. Therefore the time constant is just how long it takes for AV(t) to reach 63% of the EMF. The graph shows the voltage across a charging capacitor as a function of time. The resistance of the circuit is 7.5 kN. а. Determine the capacitance of the capacitor. 10 8 60 40 time (ms) 20 80 100 b. What is the current at t = 10 ms? Hint: the easiest way to do this is to use the loop rule. (volts) 4.
I need the see the actual MATLAB code for the Find the breakaway point on the real axis and the gain for this point. ii. Find the gain to provide two complex roots nearest the jω-axis with a damping ratio of 0.707.
An RC circuit has an emf given (in volts) by 400 cos 2t, a resistance of 100 ohms, and a capacitance of 102 farad. Initially there is no charge on the capacitor. Find the current in the circuit at time t = O 2.664 A 0.868 A 2.330 A 3.278 A 0.5 s.
I know that the current through an inductor doesn't change instantaneously, please explain with steps on how to find IL (∞)
For the circuit find an expression for the capacitor voltage for t≥0. Theswitch closes at t = 0. The capacitance is 1 / 10F the initial voltage of the capacitor is 20V. input voltage = 20v
Please answer all parts
(S+3)(s-+2s+82) b) | Answer the following: - Explain using your own words what is the meaning of initial conditions. - How can a capacitor and an inductor get an initial condition? Give an example for a capacitor circuit and another circuit for an inductor to show how these components can build this initial condition.

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