Is Part  B: Determination  of K is correct result?

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Is Part  B: Determination  of K is correct result?

Data Report Sheet: Spectrophotometric Determination of an Equilibrium
Constant.
Part A: Determination of a Calibration Curve:
Stnd.1
Std. 2
Stnd. 3
Stnd 4
Stnd. 5
Stnd. 6
(CH)
0.000204
0.000127
0.000189
|Fe(SCN)"|
Column A
060000'0
0.
0.432
0.480
0.633
0.831
0.887
Absorbance
Column E
y3 4339.8x+ 0.0258
Equation of Calibration Line:
Correlation Coefficient:
4339.8
Slope (be):
Part B: Determination of K
Expt. 1
Expt. 2
Expt. 3
Expt. 4
Expt. 5
|Fe"al
(Table 1).
0.00165
0.00165
0.00165
0.00165
0.00165
0.00066
0.00132
0.00165
66000'0
(Table 1)
[Fe(SCN)"I
0.0001135 0.000172
0.0002223
Columa F
0.001587
0.0015365 0.001478
0.0014277 0.0013904
0.000267
0.0005465 0.000818
0.0010977 0 0013904
(SCN1
148.6799
135.1678
142.2659 141.8466
134.2843
Average K: 140 448
6.
Transcribed Image Text:Data Report Sheet: Spectrophotometric Determination of an Equilibrium Constant. Part A: Determination of a Calibration Curve: Stnd.1 Std. 2 Stnd. 3 Stnd 4 Stnd. 5 Stnd. 6 (CH) 0.000204 0.000127 0.000189 |Fe(SCN)"| Column A 060000'0 0. 0.432 0.480 0.633 0.831 0.887 Absorbance Column E y3 4339.8x+ 0.0258 Equation of Calibration Line: Correlation Coefficient: 4339.8 Slope (be): Part B: Determination of K Expt. 1 Expt. 2 Expt. 3 Expt. 4 Expt. 5 |Fe"al (Table 1). 0.00165 0.00165 0.00165 0.00165 0.00165 0.00066 0.00132 0.00165 66000'0 (Table 1) [Fe(SCN)"I 0.0001135 0.000172 0.0002223 Columa F 0.001587 0.0015365 0.001478 0.0014277 0.0013904 0.000267 0.0005465 0.000818 0.0010977 0 0013904 (SCN1 148.6799 135.1678 142.2659 141.8466 134.2843 Average K: 140 448 6.
Expert Solution
Step 1

In order to check the answers, we have to plot ICE chart for the equilibrium reaction below:

Fe3+(aq) + SCN-(aq)   <-----> Fe(SCN)2+(aq) ; K = ?? 

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