Here are summary statistics for randomly selected weights of newborn girls: n=217, x 26.5 hg, s = 6.1 hg. Construct a confidence interval estimate of the mean. Use a 99% confidence level. Are these results very different fromthe confidence interval 24.7 hg

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Description: Here are summary statistics for randomly selected weights of newborn girls: n=217, x 26.5 hg, s = 6.1 hg. Construct a confidence interval estimate of the mean. Use a 99% confidence level. Are these results very different fromthe confidence interval

Given that Sample size(n) = 217 sample mean (x¯) = 26.5 Sample standard deviation (s) = 6.1…

Answered: is: n=217, x 26.5 hg, s= 6.1 hg.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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Here are summary statistics for randomly selected weights of newborn girls: n=217, x 26.5 hg, s = 6.1 hg. Construct a confidence interval estimate of the mean. Use a 99% confidence level. Are these results very different from
the confidence interval 24.7 hg<u< 27.1hg with only 17 sample values, x= 25.9 hg, and s = 1.7 hg?
What is the confidence interval for the population mean µ?
hg<u<hg (Round to one decimal place as needed.)
Are the results between the two confidence intervals very different?
O A. No, because each confidence interval contains the mean of the other confidence interval,
O B. Yes, because one confidence interval does not contain the mean of the other confidence interval.
O C. No, because the confidence interval limits are similar.
O D. Yes, because the confidence interval limits are not similar.
Click to select your answer(s).
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Expert Solution

Step 1 - writing given data

Given that

Sample size(n) = 217

sample mean ( $\bar{x}$ ) = 26.5

Sample standard deviation (s) = 6.1

confidence level = 99%

Here , Population standard deviation is unknown and sample standard deviation given so, t-confidence interval used.

degrees of freedom (df) = (n-1) = 217-1 =216

level of significance ( $α$ ) = 1- 0.99 = 0.01

$\frac{α}{2} = \frac{0.01}{2} = 0.005$

at $\frac{α}{2} = 0.005, d f = 216, o n e t a i l e d t - c r i t i c a l v a l u e = t_{c} = 2.5987$

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