is my answer to Q10 (a,b) correct, is there anything else to include also,for this question,rearrange the equilibrium expression to calculate K by putting my new products on top and new reactants on the bottom AL UNIVERSITY Q10. The magnitude of K is critical for O, to be pass first from lungs into red blood cells and then subsequently into the tissues. If K was either much smaller or much larger, then the system would not work. Now consider why not: (a) If K was very small, would the equilibrium favour reactants or products in the above reaction? How would that affect the proportion of oxygenated HbO (aq) to deoxygenated Hb(aq) in blood leaving the lungs? ANSWER: If K was very small, then the equilibrium favours towards the reactant. This implies that the proposition of oxygenated HbO₂ (aq) to deoxygenated Hb (aq) in blood leaving the lungs would be lower. This will lead to the blood to contain more haemoglobin. Now consider the equilibrium once the blood vessels have reached the tissues of the body that rely on diffusion of oxygen, Q.(aq), from the bloodstream. Hb(aq) + O₂(aq) = HbO₂(aq) K [HbO₂(aq)] [Hb(aq)]X[0₂(aq)] Q10(b) If K was very large, how would that affect the amount of O₂(aq) available to pass from blood into the tissues? (biat: Consider whether the forward or reverse reaction is required now) ANSWER: If the K was very large, the amount of oxygen will pass forward (more product will form) from blood into the tissues with the affect that there would be a higher amount of oxygenated HbO₂ (aq) in the blood than in the tissue. This will help the in the transmission of oxygen from the bloods into the tissues due to the high PO₂ in the blood.
is my answer to Q10 (a,b) correct, is there anything else to include also,for this question,rearrange the equilibrium expression to calculate K by putting my new products on top and new reactants on the bottom AL UNIVERSITY Q10. The magnitude of K is critical for O, to be pass first from lungs into red blood cells and then subsequently into the tissues. If K was either much smaller or much larger, then the system would not work. Now consider why not: (a) If K was very small, would the equilibrium favour reactants or products in the above reaction? How would that affect the proportion of oxygenated HbO (aq) to deoxygenated Hb(aq) in blood leaving the lungs? ANSWER: If K was very small, then the equilibrium favours towards the reactant. This implies that the proposition of oxygenated HbO₂ (aq) to deoxygenated Hb (aq) in blood leaving the lungs would be lower. This will lead to the blood to contain more haemoglobin. Now consider the equilibrium once the blood vessels have reached the tissues of the body that rely on diffusion of oxygen, Q.(aq), from the bloodstream. Hb(aq) + O₂(aq) = HbO₂(aq) K [HbO₂(aq)] [Hb(aq)]X[0₂(aq)] Q10(b) If K was very large, how would that affect the amount of O₂(aq) available to pass from blood into the tissues? (biat: Consider whether the forward or reverse reaction is required now) ANSWER: If the K was very large, the amount of oxygen will pass forward (more product will form) from blood into the tissues with the affect that there would be a higher amount of oxygenated HbO₂ (aq) in the blood than in the tissue. This will help the in the transmission of oxygen from the bloods into the tissues due to the high PO₂ in the blood.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please send me the question in 20 minutes it's very urgent plz find the
![Question:
is my answer to Q10 (a,b) correct, is there
anything else to include
also,for this question ,rearrange the
equilibrium expression to calculate K by
putting my new products on top and new
reactants on the bottom
UNIVERSITY
Q10. The magnitude of K is critical for O, to be pass first from lungs into red blood cells and then
subsequently into the tissues. If K was either much smaller or much larger, then the system would
not work. Now consider why not:
(a) If K was very small, would the equilibrium favour reactants or products in the above reaction?
How would that affect the proportion of oxygenated HbO (aq) to deoxygenated Hb(aq) in blood
leaving the lungs?
ANSWER:
If K was very small, then the equilibrium favours towards the reactant. This implies that the
proposition of oxygenated HbO₂ (aq) to deoxygenated Hb (aq) in blood leaving the lungs would be
lower. This will lead to the blood to contain more haemoglobin.
Now consider the equilibrium once the blood vessels have reached the tissues of the body that rely
on diffusion of oxygen, O.(aq), from the bloodstream.
Hb(aq) + O₂(aq) = HbO₂(aq)
K =
[HbO₂ (aq)]
[Hb(aq)]X[0₂(aq)]
Q10(b) If K was very large, how would that affect the amount of O₂(aq) available to pass from
blood into the tissues? (biat: Consider whether the forward or reverse reaction is required now)
ANSWER:
If the K was very large, the amount of oxygen will pass forward (more product will form) from
blood into the tissues with the affect that there would be a higher amount of oxygenated HbO₂ (aq)
in the blood than in the tissue. This will help the in the transmission of oxygen from the bloods into
the tissues due to the high PO₂ in the blood.
G](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F957a6242-1a60-46cb-823f-4a25075634cc%2Ff209ad92-a0aa-442d-b450-9077cfea6c64%2F54fo8qd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question:
is my answer to Q10 (a,b) correct, is there
anything else to include
also,for this question ,rearrange the
equilibrium expression to calculate K by
putting my new products on top and new
reactants on the bottom
UNIVERSITY
Q10. The magnitude of K is critical for O, to be pass first from lungs into red blood cells and then
subsequently into the tissues. If K was either much smaller or much larger, then the system would
not work. Now consider why not:
(a) If K was very small, would the equilibrium favour reactants or products in the above reaction?
How would that affect the proportion of oxygenated HbO (aq) to deoxygenated Hb(aq) in blood
leaving the lungs?
ANSWER:
If K was very small, then the equilibrium favours towards the reactant. This implies that the
proposition of oxygenated HbO₂ (aq) to deoxygenated Hb (aq) in blood leaving the lungs would be
lower. This will lead to the blood to contain more haemoglobin.
Now consider the equilibrium once the blood vessels have reached the tissues of the body that rely
on diffusion of oxygen, O.(aq), from the bloodstream.
Hb(aq) + O₂(aq) = HbO₂(aq)
K =
[HbO₂ (aq)]
[Hb(aq)]X[0₂(aq)]
Q10(b) If K was very large, how would that affect the amount of O₂(aq) available to pass from
blood into the tissues? (biat: Consider whether the forward or reverse reaction is required now)
ANSWER:
If the K was very large, the amount of oxygen will pass forward (more product will form) from
blood into the tissues with the affect that there would be a higher amount of oxygenated HbO₂ (aq)
in the blood than in the tissue. This will help the in the transmission of oxygen from the bloods into
the tissues due to the high PO₂ in the blood.
G
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