Is λ = 5 an eigenvalue of 40-3 44 -2 3 9? If so, find one corresponding eigenvector. 8
Is λ = 5 an eigenvalue of 40-3 44 -2 3 9? If so, find one corresponding eigenvector. 8
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![**Problem Statement:**
Is \( \lambda = 5 \) an eigenvalue of
\[
\begin{bmatrix}
4 & 0 & -3 \\
4 & 4 & 9 \\
-2 & 3 & 8
\end{bmatrix}
\]
? If so, find one corresponding eigenvector.
---
**Options:**
Select the correct choice below and, if necessary, fill in the answer box within your choice.
- **A.** Yes, \( \lambda = 5 \) is an eigenvalue of
\[
\begin{bmatrix}
4 & 0 & -3 \\
4 & 4 & 9 \\
-2 & 3 & 8
\end{bmatrix}
\]
One corresponding eigenvector is \(\_\_\).
*(Type a vector or list of vectors. Type an integer or simplified fraction for each matrix element.)*
- **B.** No, \( \lambda = 5 \) is not an eigenvalue of
\[
\begin{bmatrix}
4 & 0 & -3 \\
4 & 4 & 9 \\
-2 & 3 & 8
\end{bmatrix}
\]
**Selected Answer:**
- **B.** No, \( \lambda = 5 \) is not an eigenvalue.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a6c3af6-91f1-478b-99db-a0b0fd9518f2%2Fe0588a18-bfec-4838-a221-b836f6ed4442%2Fuv7da3h_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Is \( \lambda = 5 \) an eigenvalue of
\[
\begin{bmatrix}
4 & 0 & -3 \\
4 & 4 & 9 \\
-2 & 3 & 8
\end{bmatrix}
\]
? If so, find one corresponding eigenvector.
---
**Options:**
Select the correct choice below and, if necessary, fill in the answer box within your choice.
- **A.** Yes, \( \lambda = 5 \) is an eigenvalue of
\[
\begin{bmatrix}
4 & 0 & -3 \\
4 & 4 & 9 \\
-2 & 3 & 8
\end{bmatrix}
\]
One corresponding eigenvector is \(\_\_\).
*(Type a vector or list of vectors. Type an integer or simplified fraction for each matrix element.)*
- **B.** No, \( \lambda = 5 \) is not an eigenvalue of
\[
\begin{bmatrix}
4 & 0 & -3 \\
4 & 4 & 9 \\
-2 & 3 & 8
\end{bmatrix}
\]
**Selected Answer:**
- **B.** No, \( \lambda = 5 \) is not an eigenvalue.
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