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is it correct?If this is correct, please help me to see the red line or red circle which has the question mark. i will be very very appreciate!!

is it correct?If this is correct, please help me to see the red line or red circle which has the question mark. i will be very very appreciate!!

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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is it correct?If this is correct, please help me to see the red line or red circle which has the question mark.

i will be very very appreciate!!

A large cylindrical tank with diameter D is firmly mounted on a wagon. Water flows out of the tank through a nozzle with circular cross section and diameter d (d << D). The height of the water level above the nozzle centerline is defined by h, and the initial height is he. The flow can be assumed to be i -free. b) c) a) 4 Wasser/ water O a) Calculate the water level h(t) as a function of time as well as g. D and d if h(t = 0) ho applies. Calculate the time it takes the tank to empty (h = 0). Determine the thrust force acting on the wagon at time = 5s. For this purpose, draw an appropriate control volume. Note: If you could not solve part a), usev = √pgh. Massenerhaltung Pa Gravitational acceleration: Initial water level at - 0: Tank diameter: Nozzle diameter: Water density: he D Wasser/ water Q 1 : Bemadli-Gleichung zwischen 1 und 2 PY + PV₁²³ + 193₁ = BC + 1 PV ₁² + Pg2²₂²° 20 -Pa Wusseroberfläche Z₁ = 0 P9z₁ = PV²₂² Figure source see [3] -3 Pa 9 ho D d ho P 2√5-2√5₂ = 9.81 m/s² -0.7 m = 0.5 m 0.06 m 1000 kg/m³ V₂ = √√292₁ mit Z₁ = h = √2gh BPdv + √ut PvdA = 0 BP #D²h + Purgh #d² = 0_? D². dt = -√zigh dª and = -d in dh = -√g d² dt [^²d-²" de 2² t t e
Transcribed Image Text:A large cylindrical tank with diameter D is firmly mounted on a wagon. Water flows out of the tank through a nozzle with circular cross section and diameter d (d << D). The height of the water level above the nozzle centerline is defined by h, and the initial height is he. The flow can be assumed to be i -free. b) c) a) 4 Wasser/ water O a) Calculate the water level h(t) as a function of time as well as g. D and d if h(t = 0) ho applies. Calculate the time it takes the tank to empty (h = 0). Determine the thrust force acting on the wagon at time = 5s. For this purpose, draw an appropriate control volume. Note: If you could not solve part a), usev = √pgh. Massenerhaltung Pa Gravitational acceleration: Initial water level at - 0: Tank diameter: Nozzle diameter: Water density: he D Wasser/ water Q 1 : Bemadli-Gleichung zwischen 1 und 2 PY + PV₁²³ + 193₁ = BC + 1 PV ₁² + Pg2²₂²° 20 -Pa Wusseroberfläche Z₁ = 0 P9z₁ = PV²₂² Figure source see [3] -3 Pa 9 ho D d ho P 2√5-2√5₂ = 9.81 m/s² -0.7 m = 0.5 m 0.06 m 1000 kg/m³ V₂ = √√292₁ mit Z₁ = h = √2gh BPdv + √ut PvdA = 0 BP #D²h + Purgh #d² = 0_? D². dt = -√zigh dª and = -d in dh = -√g d² dt [^²d-²" de 2² t t e
b) () Wh-Uho 129d² 2D² Vh = Who U29 d² 2D² == - h(t) = (Who - vzg・d². 2D² Schub Who-U29 d² 2D² D Wasser/ water h = 0 (Who -√2-d² t) ² = 0 t t für t=55: Pa . t ho = t = t) ² O Who = 26, 23 S 2.D² vzg. d² R 12 Ø?? Impulserhaltung: P + F2 - BP v dv + Juf P V ( J. ñ ) d A -Fs = PV²A₂ Why this equals to F --P (29h) A₂ mit h(t) = (Who - Viqd² t) ² 2D² h(5) = 0,459 m Fs = -25,463 N
Transcribed Image Text:b) () Wh-Uho 129d² 2D² Vh = Who U29 d² 2D² == - h(t) = (Who - vzg・d². 2D² Schub Who-U29 d² 2D² D Wasser/ water h = 0 (Who -√2-d² t) ² = 0 t t für t=55: Pa . t ho = t = t) ² O Who = 26, 23 S 2.D² vzg. d² R 12 Ø?? Impulserhaltung: P + F2 - BP v dv + Juf P V ( J. ñ ) d A -Fs = PV²A₂ Why this equals to F --P (29h) A₂ mit h(t) = (Who - Viqd² t) ² 2D² h(5) = 0,459 m Fs = -25,463 N
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