is it correct?If this is correct, please help me to see the red line or red circle which has the question mark. i will be very very appreciate!!
is it correct?If this is correct, please help me to see the red line or red circle which has the question mark. i will be very very appreciate!!
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
100%
is it correct?If this is correct, please help me to see the red line or red circle which has the question mark.
i will be very very appreciate!!
![A large cylindrical tank with diameter D is firmly mounted on a wagon. Water flows out of the
tank through a nozzle with circular cross section and diameter d (d << D). The height of the
water level above the nozzle centerline is defined by h, and the initial height is he. The flow can
be assumed to be i -free.
b)
c)
a)
4
Wasser/
water
O
a) Calculate the water level h(t) as a function of time as well as g. D and d
if h(t = 0) ho applies.
Calculate the time it takes the tank to empty (h = 0).
Determine the thrust force acting on the wagon at time = 5s. For this purpose, draw
an appropriate control volume. Note: If you could not solve part a), usev = √pgh.
Massenerhaltung
Pa
Gravitational acceleration:
Initial water level at - 0:
Tank diameter:
Nozzle diameter:
Water density:
he
D
Wasser/
water
Q
1
:
Bemadli-Gleichung zwischen 1 und 2
PY + PV₁²³ + 193₁ = BC + 1 PV ₁² + Pg2²₂²°
20
-Pa Wusseroberfläche
Z₁ = 0
P9z₁ = PV²₂²
Figure source see [3]
-3
Pa
9
ho
D
d
ho
P
2√5-2√5₂ =
9.81 m/s²
-0.7 m
= 0.5 m
0.06 m
1000 kg/m³
V₂ = √√292₁ mit Z₁ = h
= √2gh
BPdv + √ut PvdA = 0
BP #D²h + Purgh #d² = 0_?
D². dt = -√zigh dª
and = -d
in dh = -√g d² dt
[^²d-²" de
2²
t
t
e](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa482f51c-60d4-424a-a66b-e3f21758d1f0%2F45bf3a46-3c47-4297-8235-4f5bd34c4ef7%2Fi06xrtb_processed.png&w=3840&q=75)
Transcribed Image Text:A large cylindrical tank with diameter D is firmly mounted on a wagon. Water flows out of the
tank through a nozzle with circular cross section and diameter d (d << D). The height of the
water level above the nozzle centerline is defined by h, and the initial height is he. The flow can
be assumed to be i -free.
b)
c)
a)
4
Wasser/
water
O
a) Calculate the water level h(t) as a function of time as well as g. D and d
if h(t = 0) ho applies.
Calculate the time it takes the tank to empty (h = 0).
Determine the thrust force acting on the wagon at time = 5s. For this purpose, draw
an appropriate control volume. Note: If you could not solve part a), usev = √pgh.
Massenerhaltung
Pa
Gravitational acceleration:
Initial water level at - 0:
Tank diameter:
Nozzle diameter:
Water density:
he
D
Wasser/
water
Q
1
:
Bemadli-Gleichung zwischen 1 und 2
PY + PV₁²³ + 193₁ = BC + 1 PV ₁² + Pg2²₂²°
20
-Pa Wusseroberfläche
Z₁ = 0
P9z₁ = PV²₂²
Figure source see [3]
-3
Pa
9
ho
D
d
ho
P
2√5-2√5₂ =
9.81 m/s²
-0.7 m
= 0.5 m
0.06 m
1000 kg/m³
V₂ = √√292₁ mit Z₁ = h
= √2gh
BPdv + √ut PvdA = 0
BP #D²h + Purgh #d² = 0_?
D². dt = -√zigh dª
and = -d
in dh = -√g d² dt
[^²d-²" de
2²
t
t
e
![b)
()
Wh-Uho
129d²
2D²
Vh = Who U29 d²
2D²
==
-
h(t) = (Who - vzg・d².
2D²
Schub
Who-U29 d²
2D²
D
Wasser/
water
h = 0
(Who -√2-d² t) ² = 0
t
t
für t=55:
Pa
.
t
ho
=
t
=
t) ²
O
Who
= 26, 23 S
2.D²
vzg. d²
R
12
Ø??
Impulserhaltung: P + F2 - BP v dv + Juf P V ( J. ñ ) d A
-Fs = PV²A₂
Why this
equals to
F --P (29h) A₂ mit h(t) = (Who - Viqd² t) ²
2D²
h(5) = 0,459 m
Fs = -25,463 N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa482f51c-60d4-424a-a66b-e3f21758d1f0%2F45bf3a46-3c47-4297-8235-4f5bd34c4ef7%2Fa8a0feb_processed.png&w=3840&q=75)
Transcribed Image Text:b)
()
Wh-Uho
129d²
2D²
Vh = Who U29 d²
2D²
==
-
h(t) = (Who - vzg・d².
2D²
Schub
Who-U29 d²
2D²
D
Wasser/
water
h = 0
(Who -√2-d² t) ² = 0
t
t
für t=55:
Pa
.
t
ho
=
t
=
t) ²
O
Who
= 26, 23 S
2.D²
vzg. d²
R
12
Ø??
Impulserhaltung: P + F2 - BP v dv + Juf P V ( J. ñ ) d A
-Fs = PV²A₂
Why this
equals to
F --P (29h) A₂ mit h(t) = (Who - Viqd² t) ²
2D²
h(5) = 0,459 m
Fs = -25,463 N
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