**Future scientists:** Education professionals refer to science, technology, engineering, and mathematics as the STEM disciplines. A research group reported that 27% of freshmen entering college in a recent year planned to major in a STEM discipline. A random sample of 85 freshmen is selected. Round the answer to at least four decimal places.**Part: 0 / 6**### Part 1 of 6**Is it appropriate to use the normal approximation to find the probability that less than 32% of the freshmen in the sample are planning to major in a STEM discipline?**It ___ appropriate to use the normal curve, since $ np = $ ___ $ \geq $ 10 and $ n(1-p) = $ ___ $ \geq $ 10.---**Part: 1 / 6****Part 2 of 6****Find the probability that less than 32% of the freshmen in the sample are planning to major in a STEM discipline.**The probability that less than 32% of the freshmen in the sample are planning to major in a STEM discipline is ___ .---**Part 3 of 6****A new sample of 130 freshmen is selected. Find the probability that less than 29% of the freshmen in this new sample are planning to major in a STEM discipline.**The probability that less than 29% of the freshmen in the sample are planning to major in a STEM discipline is ___ .---### Explanation and Diagrams OverviewThis image outlines a statistical exercise involving probabilities and normal approximation for proportions in a sample related to freshmen majoring in STEM disciplines. The exercise is divided into parts, each with different requirements, including determining normal curve applicability and calculating probabilities.There are interactive elements in the image such as buttons for input and selection that would be used to fill in the missing information or compute values as part of the exercise. **Part 4 of 6**Find the probability that the proportion of freshmen in the sample of 130 who plan to major in a STEM discipline is between 0.29 and 0.34.The probability that the proportion of individuals in the sample of 130 who plan to major in a STEM discipline is between 0.29 and 0.34 is [text box].**Part 5 of 6**Find the probability that more than 32% of the freshmen in the sample of 130 are planning to major in a STEM discipline.The probability that more than 32% of the freshmen in the sample of 130 are planning to major in a STEM discipline is [text box].**Progress Indicator**Displayed as a progress bar labeled "Part: 5 / 6."**Part 6 of 6**Would it be unusual if less than 24% of the freshmen in the sample of 130 were planning to major in a STEM discipline?It [dropdown menu labeled "Choose one"] be unusual if less than 24% of the freshmen in the sample of 130 were planning to major in a STEM discipline, since the probability is [text box].

Let p be the proportion of freshmen planning to major in STEM discipline. Given that p = 27% = 0.27 Note : According to our guidelines we are solving only first three sub parts of a question and the rest parts may be reposted.

Answered: Is it appropriate to use the normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The table below shows the number of hours per day 11 patients suffered from headaches before and after 7 weeks of soft tissue therapy. At a =0.01, is there enough evidence to conclude that soft tissue therapy helps to reduce the length of time patients suffer from headaches? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (n- 7 89 10 11 0 1 2 3 Patient Daily headache hours (before) 2.9 3.2 3.4 1.8 Daily headache hours (after) 4 5 4.4 1.8 3.8 2.5 1.8 3.3 3.8 1.7 3.6 2.2 1.1 1.1 1.4 3.5 2.2 1.2 2.9 4.3 (a) Identify the claim and state Ho and H The claim is "The therapy helps to reduce the length of time patients suffer from headaches." Let Ha be the hypothesized mean of the patients' daily headache hours before therapy minus their daily headache hours after it. State Ho and H. Choose the correct answer below. OC. Ho: Hg #d B. Ho: Ha s0 H P0 OA Ho: Ha sd H, >d O D. Ho: Hg 20 H H <0 OE Ho: Ha=d OF. Ho: Hg zd (b) Find the…
Data from an experiment show that the standard deviation is 3.6 and the mean is 23.4. Find the probability that the reading from the experiment is more than 32
An Industrial Organizational (IO) psychologist got some data from a test they did on productivity. The They collected productivity scores (from 1-100 points) from n=5 participants. The scores were: 78, 85, 64, 90 and 88. Find the mean of this group. Suppose the population parameters are µ=75 and o = 12, what is the SEM for this particular group? What is the z score? Draw out and shade the curve and determine what the probability of getting this mean is.
8 We want to find the probability that the risk of a hazard will not occur in a system. Given two scenarios are “no risk,” and all other scenarios have “risk”. The probabilities of the two “no risk” scenarios are estimated as p1= 0.87 and p2= 0.98. The corresponding standard deviations are s1 = 0.03 and s2 = 0.06. Find the mean and standard deviation of the overall system success (no risk) and system failure (risk).
MORE BENEFITS OF EATING ORGANIC Using specific data, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data. In this case, we are testing where p, and p, represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % significance level. Effect of Organic Bananas After 25 Days After 25 days, the proportion of fruit flies eating organic bananas still alive is 0.45, while the proportion still alive eating conventional bananas is 0.43. The standard error for the difference in proportions is 0.029. What is the value of the test statistic? Round your answer to two decimal places. Z= What is the p-value? Round your answer to three decimal places. p-value = i Ho: Po = Pc Ha: Po > Pe What is…
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Thirteen percent of U.S. employees who are late for work blame oversleeping. You randomly select four U.S. employees who are late for work and ask them whether they blame oversleeping. The random variable represents the number of U.S. employees who are late for work and blame oversleeping. Find the mean of the binomial distribution. u= (Round to the nearest hundredth as needed.) Find the variance of the binomial distribution. g2 = (Round to the nearest hundredth as needed.) Find the standard deviation of the binomial distribution. (Round to the nearest hundredth as needed.) Interpret the results in the context of the real-life situation. In most samples of four adults are late for work, the average number of adults that blame oversleeping would differ from the mean by no more than (Type an integer or decimal rounded to the nearest hundredth as needed.)
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An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you that the printing speed is actually a Normal random variable with a mean of 17.57 ppm and a standard deviation of 3 ppm. Suppose that you draw a random sample of 11 printers. Part i) Suppose the number of printers drawn is quadrupled. How will the standard deviation of sample mean printing speed change? O A. It will decrease by a factor of 4. O B. It will increase by a factor of 4. OC. It will increase by a factor of 2. OD. It will decrease by a factor of 2. OE. It will remain unchanged. Part ii) Suppose the number of printers drawn is quadrupled. How will the mean of the sample mean printing speed change? O A. It will increase by a factor of 4. OB. It will decrease by a factor of 2. OC. It will increase by a factor of 2. O D. It will decrease by a factor of 4. OE. It will remain unchanged. Part iii) Consider the statement: 'The distribution of the mean printing…
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