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is equal to sec (2x) + In|sec(2x)|+ C sec (2x) – In|sec(2x)| + C the above the above Gsec (2x) – In|sec(2x)l) + C Esec (2x) + In/sec(2x)l) + C the above the above

is equal to sec (2x) + In|sec(2x)|+ C sec (2x) – In|sec(2x)| + C the above the above Gsec (2x) – In|sec(2x)l) + C Esec (2x) + In/sec(2x)l) + C the above the above

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Using appropriate substitution, [sec³ (2x) – 1] tan(2x) dx is equal to sec (2x) + In|sec(2x)|+ sec (2x) – In|sec(2x)| + C the above the above (sec" (2x) – In|sec(2x)) + C Gsec"(2x) + In|sec(2x)) + C the above the above
Transcribed Image Text:Using appropriate substitution, [sec³ (2x) – 1] tan(2x) dx is equal to sec (2x) + In|sec(2x)|+ sec (2x) – In|sec(2x)| + C the above the above (sec" (2x) – In|sec(2x)) + C Gsec"(2x) + In|sec(2x)) + C the above the above
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