is a Below of charge. Shell has partial shell density (6) and radius (a). Shell extends in theta from 0 = 0 0 = 06 and Ĵ zero It is centered on area element, A to S centered on origin where you = C charge element, do = distance, So-called integrand, SS lower bound of @ integral :: Upper bound of cos(a)= origin where you will find the electric field. is complete n & integral: lower bound of 4 integral: "upper bound of 4 integral: final result of integrations dQ 2 & direction. de Aplease use k in and don't use E answers
is a Below of charge. Shell has partial shell density (6) and radius (a). Shell extends in theta from 0 = 0 0 = 06 and Ĵ zero It is centered on area element, A to S centered on origin where you = C charge element, do = distance, So-called integrand, SS lower bound of @ integral :: Upper bound of cos(a)= origin where you will find the electric field. is complete n & integral: lower bound of 4 integral: "upper bound of 4 integral: final result of integrations dQ 2 & direction. de Aplease use k in and don't use E answers
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Below is a
Shell has
partial shell
density (6) and radius (a), shell extends in theta
from 0 = 0
0 = 06
and
It is
zero
to
S
area element, A C
charge element, dQ =
distance,
So-called, cos(a) =
integrand, SS
lower bound of o integral =
Upper bound of
centered on origin where you will find the eledriz
field.
& integral:
lower bound of s integral:
upper bound of
final
of charge.
& integral:
result of integrations
is complete n
dQ
2
1²
& direction.
9
dE
please use
and don't use
y
k in answers
E
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