CNNBC recently reported that the mean annual cost of auto insurance is 1048 dollars. Assume the standarddeviation is 204 dollars, and the cost is normally distributed. You take a simple random sample of 40 autoinsurance policies. Round your answers to 4 decimal places.a. What is the distribution of X? X - N( 1048b. What is the distribution of ? ~ N( 10481048x) 0 1048c. What is the probability that one randomly selected auto insurance is more than $1047?✓,204or ord. a simple random sample of 40 auto insurance policies, find the probability that the average cost ismore than $1047.e. For part d), is the assumption of normal necessary? O No Yes

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Answered: is 204 dollars, and the cos normally…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average final exam score for the statistics course is 82%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is different. The final exam scores for the 14 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 90, 78, 82, 59, 67, 71, 64, 78, 67, 57, 79, 86, 66, 56 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use (t-test for a population mean, z-test for a population proportion) The null and alternative hypotheses would be: H0: (symbol) (symbol) ____ H1: (symbol) (symbol) ____ The test statistic (?,t,z) = ____ (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is (symbol) αα Based on this, we should (accept, reject, fail to reject) the null hypothesis.…
Find the mean and variance of the number of games in the World Series. Assume we have two teams, A and B. Recall that it is won by the first team to win four out of the seven games and assume that the outcomes are determined by flipping a coin.
The average final exam score for the statistics course is 43%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is larger. The final exam scores for the 19 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 54, 38, 45, 47, 42, 42, 48, 38, 56, 51, 46, 41, 43, 41, 37, 40, 53, 43, 43 Copy to clipboard What can be concluded at the = 0.05 level of the significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H1: ? Select an answer c. The test statistic ? v (please show your answer to 3 decimal places.)
The average final exam score for the statistics course is 74%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is different. The final exam scores for the 14 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 71, 72, 53, 61, 75, 55, 75, 74, 58, 50, 71, 84, 76, 53 What can be concluded at the the αα = 0.10 level of significance level of significance? The null and alternative hypotheses would be: H0: μ = ______________ H1: μ ≠ ______________ The test statistic t= ________________(please show your answer to 3 decimal places.) The p-value = _______________________ (Please show your answer to 4 decimal places.)
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K The following data represent the number of drivers involved in a fatal crash in 2016 in various light and weather conditions. Complete parts (a) through (c) below. Click the icon to view the data for fatal crashes in 2016. (a) Among fatal crashes in unknown weather conditions, what is the probability that a randomly selected fatal crash occurs when it is dawn/dusk? The probability that a randomly selected fatal crash in unknown weather conditions occurs when it is dawn/dusk is approximately. (Round to three decimal places as needed.) Data table Weather Daylight Dark, but Lighted 5875 497 51 54 255 Normal Rain Snow/Sleet Other Unknown 14,307 875 219 125 810 (...) Dark 8151 681 156 220 548 Dawn/Dusk Other 1183 87 40 71 65 8 2 9 133 X

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