Iron packs in a body-centered cubic structure. If an iron atom has a radius of 126 pm, what is the distance between lattice points at two opposite corners of the unit cell? (Note: a line drawn between the points would go through the center of the unit cell) 3(126 pm) = 218 pm a. %3D O b. 4(126 pm) = 504 pm %3D C. 2 (126 pm) = 109 pm o d. 2(126 pm) = 252 pm !! VZ(126 pm) = 178 pm e. %3D

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Iron packs in a body-centered cubic structure. If an iron atom has a radius of 126
pm, what is the distance between lattice points at two opposite corners of the
unit cell? (Note: a line drawn between the points would go through the center of
the unit cell)
3(126 pm) = 218 pm
%3D
Ob. 4(126 pm) = 504 pm
C.
(126 pm)%3D 109 pm
2.
O d. 2(126 pm) = 252 pm
o e. Z(126 pm) = 178 pm
P Type here to search
M ゆ
Transcribed Image Text:Iron packs in a body-centered cubic structure. If an iron atom has a radius of 126 pm, what is the distance between lattice points at two opposite corners of the unit cell? (Note: a line drawn between the points would go through the center of the unit cell) 3(126 pm) = 218 pm %3D Ob. 4(126 pm) = 504 pm C. (126 pm)%3D 109 pm 2. O d. 2(126 pm) = 252 pm o e. Z(126 pm) = 178 pm P Type here to search M ゆ
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