Iron is obtained from iron ore according to the following reaction:          Fe2O3      +       CO    →       Fe     +      CO2        (unbalanced) a. Assuming the blast furnace is 90.0 % efficient in recovering the iron, what is the actual mass of  iron obtainable from a ton of ore?  1 ton = 2000.0 lb     1 lb = 453.6 g

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7.  Iron is obtained from iron ore according to the following reaction:

         Fe2O3      +       CO    →       Fe     +      CO       (unbalanced)

a. Assuming the blast furnace is 90.0 % efficient in recovering the iron, what is the actual mass

of  iron obtainable from a ton of ore?  1 ton = 2000.0 lb     1 lb = 453.6 g

 

 

 

 

 

 

Answer_____________

 

   b.  What is theoretical yield of iron if 200.0 g of Fe2O3  reacts with 100.0 g of CO? 

 

 

 

Answer__________________

  c.How many grams of excess reactant are left at the end of the reaction?

 

 

 

 

Answer__________________

Expert Solution
Step 1

The balanced reaction is given by-

Fe2O3 + 3 CO = 2 Fe + 3 CO2

(a) 1 tone of iron ore

1 tone = 2000 x 453.6 g = 907200 g

Molar mass of Fe2O3 =159.70 g/mol

So, 159.70 g of Fe2O3 =1 mol

1 g of Fe2O3 = (1 / 159.70) mol

907200 g of Fe2O3

= (907200 / 159.70) mol

= 5680.65 mol

Now,

Fe2O3 + 3 CO = 2 Fe + 3 CO2

In the above reaction equation,

1 mole of Fe2O3 (iron ore) produces 2 moles of Fe.

5680.65 mole of Fe2O3 (iron ore) produces (5680.65 x 2) moles of Fe.

5680.65 mole of Fe2O3 (iron ore) produces 11361.3 moles of Fe.

Now, molar mass of Fe = 55.85 g/mol

So, 1 mole of Fe = 55.85 g

11361.3 moles of Fe

 = 11361.3 x 55.85 g = 634528.61 g

 

 

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