IR Spectrum 2984 (liquid film) 4000 100 43 80 60 I- M+= 88 40 20 40 80 لللللللل % of base peak 29 3000 13C NMR Spectrum (50.0 MHz, CDCI 3 solution) 10 DEPT CH₂ CH3 CH proton decoupled ¹H NMR Spectrum (200 MHz, CDCI solution) 9 200 8 2000 v (cm¹) 120 160 m/e 1741 160 7 www.m 1243 1600 1 6 1200 120 800 Mass Spectrum 200 240 280 5 C4H8O2 solvent m 80 4. 0.0 0.5 1.0 1.5 200 3 40 UV spectrum solvent ethanol 15.4 mg / 10 mls path length 1.00 cm 250 300 λ (nm) 2 350 08 (ppm) 1 TMS 1 0 8 (ppm)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given the following NMR data, find the unknown compound. 

a. Identify the molecular formula; find IHD
b. Identify the 1H and 13C NMR signals

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1741
IR Spectrum
4000
8 8 8 8
(liquid film)
100H
43
80
60
H-
40
29
M+ = 88
20
40
% of base peak
10
2984
3000
13C NMR Spectrum
(50.0 MHz, CDCI 3 solution)
proton decoupled
DEPT CH₂ CH3 CH
1
9
80
200
¹H NMR Spectrum
(200 MHz, CDCI 3 solution)
2000
8
120
V (cm²¹)
m/e
160
160
7
1600
6
200
120
1243
1200
Mass Spectrum
240
800
5
C4H8O2
280
solvent
80
4
0.0
0.5
1.0
5
1.5
200
3
40
UV spectrum
solvent ethanol
15.4 mg / 10 mls
path length: 1.00 cm
250
2
...
300
λ (nm)
Il
350
0 8 (ppm)
1
TMS
1
0
8 (ppm)
Transcribed Image Text:www 1741 IR Spectrum 4000 8 8 8 8 (liquid film) 100H 43 80 60 H- 40 29 M+ = 88 20 40 % of base peak 10 2984 3000 13C NMR Spectrum (50.0 MHz, CDCI 3 solution) proton decoupled DEPT CH₂ CH3 CH 1 9 80 200 ¹H NMR Spectrum (200 MHz, CDCI 3 solution) 2000 8 120 V (cm²¹) m/e 160 160 7 1600 6 200 120 1243 1200 Mass Spectrum 240 800 5 C4H8O2 280 solvent 80 4 0.0 0.5 1.0 5 1.5 200 3 40 UV spectrum solvent ethanol 15.4 mg / 10 mls path length: 1.00 cm 250 2 ... 300 λ (nm) Il 350 0 8 (ppm) 1 TMS 1 0 8 (ppm)
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