Iř bị, b2 form an orthonormal basis for C and x is any vector in C?, then O x[4 – 2 |x - b1|² |x - b2 = |x - b1|* + |x - bg|* O None of the given options is correct O x|4 + x - bi|* – 2 |x - b1 |x · b2 |x|4 – |x · b1| O x4 – |x · bị* - |x - b2|* = 0 = |x - b24 2 x - bị |x · b2|² + |x · b2|

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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If bị, b2 form an orthonormal basis for C2 and x is any vector in C2, then
|x|4 – 2 |x - b1 |x - b2 = |x - b1|* + |x - b2|*
O None of the given options is correct
|x|4 + |x · b1* – 2 |x · b1 |x · b2 = | |*
· b2²
x- b2
-
O x|4 – |x · bi|
O
2 x . bị x · b22
+ |x · b22
|x|4 – |x - b1* – |x - b2* = 0
Transcribed Image Text:If bị, b2 form an orthonormal basis for C2 and x is any vector in C2, then |x|4 – 2 |x - b1 |x - b2 = |x - b1|* + |x - b2|* O None of the given options is correct |x|4 + |x · b1* – 2 |x · b1 |x · b2 = | |* · b2² x- b2 - O x|4 – |x · bi| O 2 x . bị x · b22 + |x · b22 |x|4 – |x - b1* – |x - b2* = 0
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