Investigative Team The state narcotics bureau must form a 5-member investigative team. If it has 30 agents from which to choose, how many different possible teams can be formed? There are ways to choose a team of 5 out of 30 agents.

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### Investigative Team Selection

The state narcotics bureau must form a 5-member investigative team. If it has 30 agents from which to choose, how many different possible teams can be formed?

**Question:**  
There are ____ ways to choose a team of 5 out of 30 agents.

**Explanation for Website:**

In this scenario, we need to determine how many distinct 5-member teams can be formed from a pool of 30 agents. This is a classic combination problem in combinatorics, where the order of selection does not matter.

To find the number of combinations, we use the combination formula:

\[ C(n, k) = \frac{n!}{k!(n-k)!} \]

where:
- \( n \) is the total number of items (agents, in this case),
- \( k \) is the number of items to choose (team members).

Plugging in the values:

\[ C(30, 5) = \frac{30!}{5!(30-5)!} \]

Calculating this will give the number of different ways to choose a team of 5 out of 30 agents.

### Graphs and Diagrams

*Note:* There are no diagrams or graphs in this image. The image merely has a blank space for the answer and two buttons, one with an 'X' and one with a circular arrow indicating reset, likely for clearing and trying again.
Transcribed Image Text:### Investigative Team Selection The state narcotics bureau must form a 5-member investigative team. If it has 30 agents from which to choose, how many different possible teams can be formed? **Question:** There are ____ ways to choose a team of 5 out of 30 agents. **Explanation for Website:** In this scenario, we need to determine how many distinct 5-member teams can be formed from a pool of 30 agents. This is a classic combination problem in combinatorics, where the order of selection does not matter. To find the number of combinations, we use the combination formula: \[ C(n, k) = \frac{n!}{k!(n-k)!} \] where: - \( n \) is the total number of items (agents, in this case), - \( k \) is the number of items to choose (team members). Plugging in the values: \[ C(30, 5) = \frac{30!}{5!(30-5)!} \] Calculating this will give the number of different ways to choose a team of 5 out of 30 agents. ### Graphs and Diagrams *Note:* There are no diagrams or graphs in this image. The image merely has a blank space for the answer and two buttons, one with an 'X' and one with a circular arrow indicating reset, likely for clearing and trying again.
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