Inverse Matrix To find the inverse of the matrix Use A-1 to solve the system Ax = bwhere x = | 2, Jand b = 1 -1 A = 1 -1 -6 2 3 Begin by adjoining the identity matrix to A to form the following matrix 1 -1 010 0 [ | I]= 1 -10 1 0 -6 2 30 0 1 I2 = to obtain [I | A], we apply elementary row operations in the following way 1 -1 1 0 R2 + (-1) R + R2 1 -1 -1 1 -6 3 0 0 1 23 = Note f arise, input exact fractions. For example, if your answer is - write -2/3.
Inverse Matrix To find the inverse of the matrix Use A-1 to solve the system Ax = bwhere x = | 2, Jand b = 1 -1 A = 1 -1 -6 2 3 Begin by adjoining the identity matrix to A to form the following matrix 1 -1 010 0 [ | I]= 1 -10 1 0 -6 2 30 0 1 I2 = to obtain [I | A], we apply elementary row operations in the following way 1 -1 1 0 R2 + (-1) R + R2 1 -1 -1 1 -6 3 0 0 1 23 = Note f arise, input exact fractions. For example, if your answer is - write -2/3.
Chapter7: Systems Of Equations And Inequalities
Section7.6: Solving Systems With Gaussian Elimination
Problem 3SE: Is there only one correct method of using row operations on a matrix? Try to explain two different...
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![Inverse Matrix
To find the inverse of the matrix
Use A-1 to solve the system Ax = bwhere x =
X2 Jand b =
1
1
-1
A =
1
-1
–6
3
Begin by adjoining the identity matrix to A to form the following matrix
1
-1
0 100
-10 10
30 0 1
1
=
-6
to obtain [I | A1], we apply elementary row operations in the following way
1
-1
1 0 0
R2 + (-1) R1 → R2
1
-1
-1 1 0
-6
0 0 1
23 =
Note f arise, input exact fractions. For example, if your answer is - write -2/3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5909bef-ac29-4b8c-b4b1-b9f5e26ca729%2F96062a5e-afed-49f7-8a0c-95db93874963%2F1f6byy8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Inverse Matrix
To find the inverse of the matrix
Use A-1 to solve the system Ax = bwhere x =
X2 Jand b =
1
1
-1
A =
1
-1
–6
3
Begin by adjoining the identity matrix to A to form the following matrix
1
-1
0 100
-10 10
30 0 1
1
=
-6
to obtain [I | A1], we apply elementary row operations in the following way
1
-1
1 0 0
R2 + (-1) R1 → R2
1
-1
-1 1 0
-6
0 0 1
23 =
Note f arise, input exact fractions. For example, if your answer is - write -2/3.
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