Introduction Alkyl halides may undergo elimination reactions with Brønstead-Lowry bases in which the halide and an adjacent proton are lost to form a new π bond. Because of the loss of a proton and a halide anion the reactions are termed 'dehydrohalogenation'. The two most common associated mechanisms are designated as either unimolecular (E1) or bimolecular (E2) elimination reactions based on reaction rate studies. E1 reactions proceed via a two-step mechanism that involves the cleavage of the leaving group (here the halide) carbon bond to form a carbonium ion intermediate (slow step) that is followed by the transfer of a B-proton to a base (which can be quite weak and is usually the solvent) and the formation of the new π bond (fast step). Since the first step of the E1 is rate determining, the reaction is dependent only upon the concentration of the alkyl halide and not the concentration of the base. However, dehydrohalogentation reactions most commonly proceed via the E2 mechanism where the base abstracts a B-hydrogen atom at the same time as the halide ion is leaving to generate the new double bond. This one-step (concerted) mechanism proceeds through a single transition state and E2 reactions are termed 'bimolecular' because the rate at which they proceed is proportional to the multiplication product of the concentrations of both the alkyl halide and the base. Several factors must be considered to predict which elimination mechanism, E1 or E2, is likely a better description of the reaction. These are the strength of the base, concentration of attacking species, stability of the leaving group (halide anion), nature of the substrate, and solvent effects. This experiment is a case is an E2 elimination - in fact two of them. The action of potassium hydroxide in alcoholic solution on compounds containing halogen atoms on adjacent atoms (1,2-dihalides) results in the elimination of two molecules of hydrogen halide (double elimination) and the formation of two new π bonds to give a carbon-carbon triple bond. In this experiment you will perform a double elimination on the stilbene dibromide produced in the lab period two weeks previous (Experiment 5, Part 1) to synthesize the alkyne 1,2- diphenylacetylene according to the following reaction equation: H Br triethylene glycol + 2 KOH +2KBr + 2H₂O Br diphenylacetylene meso-1,2-dibromo-1,2-diphenylethane The final product will be characterized by TLC and UV-Vis spectroscopy. An overview of UV-Vis spectroscopy is provided in the textbook (9.2.4 in Ogilvie, 2018; 15.1-15.3 in Karty, 2014). The characteristic features of each compound in UV-Vis spectroscopy are the wavelength of maximum light absorbance (max) and the molar absorptivity or extinction coefficient ( or sometimes a), as given by the Beer-Lambert law (or Beer's Law): A = Ebc and A = absorbance (unitless), b (sometimes I) = path length (in cm), and c = concentration (in M). The units for & are therefore M-¹cm¹¹. CH
Introduction Alkyl halides may undergo elimination reactions with Brønstead-Lowry bases in which the halide and an adjacent proton are lost to form a new π bond. Because of the loss of a proton and a halide anion the reactions are termed 'dehydrohalogenation'. The two most common associated mechanisms are designated as either unimolecular (E1) or bimolecular (E2) elimination reactions based on reaction rate studies. E1 reactions proceed via a two-step mechanism that involves the cleavage of the leaving group (here the halide) carbon bond to form a carbonium ion intermediate (slow step) that is followed by the transfer of a B-proton to a base (which can be quite weak and is usually the solvent) and the formation of the new π bond (fast step). Since the first step of the E1 is rate determining, the reaction is dependent only upon the concentration of the alkyl halide and not the concentration of the base. However, dehydrohalogentation reactions most commonly proceed via the E2 mechanism where the base abstracts a B-hydrogen atom at the same time as the halide ion is leaving to generate the new double bond. This one-step (concerted) mechanism proceeds through a single transition state and E2 reactions are termed 'bimolecular' because the rate at which they proceed is proportional to the multiplication product of the concentrations of both the alkyl halide and the base. Several factors must be considered to predict which elimination mechanism, E1 or E2, is likely a better description of the reaction. These are the strength of the base, concentration of attacking species, stability of the leaving group (halide anion), nature of the substrate, and solvent effects. This experiment is a case is an E2 elimination - in fact two of them. The action of potassium hydroxide in alcoholic solution on compounds containing halogen atoms on adjacent atoms (1,2-dihalides) results in the elimination of two molecules of hydrogen halide (double elimination) and the formation of two new π bonds to give a carbon-carbon triple bond. In this experiment you will perform a double elimination on the stilbene dibromide produced in the lab period two weeks previous (Experiment 5, Part 1) to synthesize the alkyne 1,2- diphenylacetylene according to the following reaction equation: H Br triethylene glycol + 2 KOH +2KBr + 2H₂O Br diphenylacetylene meso-1,2-dibromo-1,2-diphenylethane The final product will be characterized by TLC and UV-Vis spectroscopy. An overview of UV-Vis spectroscopy is provided in the textbook (9.2.4 in Ogilvie, 2018; 15.1-15.3 in Karty, 2014). The characteristic features of each compound in UV-Vis spectroscopy are the wavelength of maximum light absorbance (max) and the molar absorptivity or extinction coefficient ( or sometimes a), as given by the Beer-Lambert law (or Beer's Law): A = Ebc and A = absorbance (unitless), b (sometimes I) = path length (in cm), and c = concentration (in M). The units for & are therefore M-¹cm¹¹. CH
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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