Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X8- X5 = Xa is free 60 X5 = Xa is free 904 X₂A X, is free X₂ Á X3² II 100 130 %4 D *5 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. A. B. OC. O D. x₁ = X, is free x₂ = x₂ = X3 = X₂ is free X4 is free II II *1 X5² X is free E p%8 F 90 90 X₁ = X₂ is free X3 = X4= X5 is free X₂ is free
Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X8- X5 = Xa is free 60 X5 = Xa is free 904 X₂A X, is free X₂ Á X3² II 100 130 %4 D *5 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. A. B. OC. O D. x₁ = X, is free x₂ = x₂ = X3 = X₂ is free X4 is free II II *1 X5² X is free E p%8 F 90 90 X₁ = X₂ is free X3 = X4= X5 is free X₂ is free
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Intersections in England are often constructed as one-way
"roundabouts," such as the one shown in the figure. Assume that
traffic must travel in the directions shown. Find the general
solution of the network flow. Find the smallest possible value for
X8-
X5 =
Xa is free
60
X5 =
Xa is free
904
X₂A
X, is free
X₂
Á
X3²
II
100 130
%4 D
*5
What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice.
A.
B.
OC.
O D.
x₁ =
X, is free
x₂ =
x₂ =
X3 =
X₂ is free
X4 is free
II
II
*1
X5²
X is free
E
p%8
F
90
90
X₁ =
X₂ is free
X3 =
X4=
X5 is free
X₂ is free
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