Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6- O A. X₁ is free *2= x3 = || X4= X5 = X is free O B. x₁ = x2 = X3 = X4= X5 = Xe is free ... O C. 60> 100 x₁ = X₂ is free x3 = X4= X5 is free X6 is free B 821 110 150 X4 D 55 X1 1x5 F O D. 100 100 X₁ is free x₂ = X3 is free X4 is free X5 = X6 is free

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Intersections in England are often constructed as one-way
"roundabouts," such as the one shown in the figure. Assume that
traffic must travel in the directions shown. Find the general
solution of the network flow. Find the smallest possible value for
X6
O A.
X₁ is free
*2=
x3 =
||
X4=
X5 =
X is free
O B.
x₁ =
x2 =
X3 =
X4=
X5 =
Xe is free
O C.
60>
100
x₁ =
X₂ is free
X3 =
X5 is free
X6 is free
B
821
110 150
83
X4 D
$5
X1
1x5
F
O D.
100
100
X₁ is free
x₂ =
X3 is free
X4 is free
X5 =
X6 is free
Transcribed Image Text:Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6 O A. X₁ is free *2= x3 = || X4= X5 = X is free O B. x₁ = x2 = X3 = X4= X5 = Xe is free O C. 60> 100 x₁ = X₂ is free X3 = X5 is free X6 is free B 821 110 150 83 X4 D $5 X1 1x5 F O D. 100 100 X₁ is free x₂ = X3 is free X4 is free X5 = X6 is free
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