Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6- O A. X₁ is free *2= x3 = || X4= X5 = X is free O B. x₁ = x2 = X3 = X4= X5 = Xe is free ... O C. 60> 100 x₁ = X₂ is free x3 = X4= X5 is free X6 is free B 821 110 150 X4 D 55 X1 1x5 F O D. 100 100 X₁ is free x₂ = X3 is free X4 is free X5 = X6 is free

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