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Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6- x₂ = X3 is free X4 is free X5 = X6 is free O B. X₂ is free X3 = X4= X5 is free x6 is free O C. X2 x₁ is free || X3 = x² 40 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. O A. X₁ is free 110 II B. X5 = X6 is free 110 130 %4 %3 X5 31 E 186 F O D. x₁ = x₂ = x3 = X4 -60 = 110 X5 = X6 is free

Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6- x₂ = X3 is free X4 is free X5 = X6 is free O B. X₂ is free X3 = X4= X5 is free x6 is free O C. X2 x₁ is free || X3 = x² 40 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. O A. X₁ is free 110 II B. X5 = X6 is free 110 130 %4 %3 X5 31 E 186 F O D. x₁ = x₂ = x3 = X4 -60 = 110 X5 = X6 is free

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6- x₂ = X3 is free X4 is free X5 = X6 is free O B. X₂ is free X3 = X4= X5 is free x6 is free O C. X2 x₁ is free II X3 = x² 40 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. O A. X₁ is free 110 11 B. X5 = X6 is free 110 130 %4 %3 X5 31 E 186 F O D. x₁ = x₂ = x3 = X4 -60 = 110 X5 = X6 is free
Transcribed Image Text:Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6- x₂ = X3 is free X4 is free X5 = X6 is free O B. X₂ is free X3 = X4= X5 is free x6 is free O C. X2 x₁ is free II X3 = x² 40 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. O A. X₁ is free 110 11 B. X5 = X6 is free 110 130 %4 %3 X5 31 E 186 F O D. x₁ = x₂ = x3 = X4 -60 = 110 X5 = X6 is free
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