Interpret the slope for PROP_CHANGE_INCOME if appropriate. If not, argue why. Estimated model = 97.23184 - 1.94182(proportion of change in household income over the past several yeares + 0.56185(proportion of free school lunch participation)
Interpret the slope for PROP_CHANGE_INCOME if appropriate. If not, argue why. Estimated model = 97.23184 - 1.94182(proportion of change in household income over the past several yeares + 0.56185(proportion of free school lunch participation)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
- Interpret the slope for PROP_CHANGE_INCOME if appropriate. If not, argue why.
Estimated model = 97.23184 - 1.94182(proportion of change in household income over the past several yeares + 0.56185(proportion of free school lunch participation)
![f) Test the significance of the slope for PROP_LUNCH in the model in part b). Don't forget to specify the null and
alternative hypothesis, test statistic, degrees of freedom, p-value, decision and conclusion in the words of the
problem. Use level of significance 5%.
Ho: B₁ = 0 vs. H₁: B₁ * 0
α = 0.05
Based on the SAS output:
t = 2.99, df-n-2=40-2=38
p-value = 0.0048<0.05
Decision: Since the p-value is less than 0.05, we reject the null hypothesis.
This data provides sufficient evidence to support the conclusion that the correlation between crime rate and the
proportion of free school lunch participation is significant on a level of significance 5%. Furthermore, the data
supports the hypothesis that the proportion of free school lunch participation and crime rate are significantly
associated on a level of significance 5%.
g) Interpret the slope for PROP_LUNCH if appropriate. If not, argue why.
h) Test the significance of the slope for PROP_CHANGE_INCOME in the model in part b). Don't forget to specify the
null and alternative hypothesis, test statistic, degrees of freedom, p-value, decision and conclusion in the words of
the problem. Use level of significance 5%.
Ho: B₂ = 0 vs. H₁: B₂ #0
α = 0.05
Based on the SAS output:
t= -2.30, df=n-2=40-2=38
p-value = 0.0270 <0.05
Decision: Since the p-value is less than 0.05, we reject the null hypothesis.
This data provides sufficient evidence to support the conclusion that the correlation between crime rate and the
proportion of change in household income over the past several years is significant on a level of significance 5%.
Furthermore, the data supports the hypothesis that the proportion of change in household income over the past
several years and crime rate are significantly associated on a level of significance 5%.
i) Interpret the slope for PROP_CHANGE_INCOME if appropriate. If not, argue why.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fff0b45d0-95e9-4516-aa8d-2049cab09c1c%2Fd5180b63-39cb-48c7-823a-7431ed49e5dc%2F4q691d_processed.png&w=3840&q=75)
Transcribed Image Text:f) Test the significance of the slope for PROP_LUNCH in the model in part b). Don't forget to specify the null and
alternative hypothesis, test statistic, degrees of freedom, p-value, decision and conclusion in the words of the
problem. Use level of significance 5%.
Ho: B₁ = 0 vs. H₁: B₁ * 0
α = 0.05
Based on the SAS output:
t = 2.99, df-n-2=40-2=38
p-value = 0.0048<0.05
Decision: Since the p-value is less than 0.05, we reject the null hypothesis.
This data provides sufficient evidence to support the conclusion that the correlation between crime rate and the
proportion of free school lunch participation is significant on a level of significance 5%. Furthermore, the data
supports the hypothesis that the proportion of free school lunch participation and crime rate are significantly
associated on a level of significance 5%.
g) Interpret the slope for PROP_LUNCH if appropriate. If not, argue why.
h) Test the significance of the slope for PROP_CHANGE_INCOME in the model in part b). Don't forget to specify the
null and alternative hypothesis, test statistic, degrees of freedom, p-value, decision and conclusion in the words of
the problem. Use level of significance 5%.
Ho: B₂ = 0 vs. H₁: B₂ #0
α = 0.05
Based on the SAS output:
t= -2.30, df=n-2=40-2=38
p-value = 0.0270 <0.05
Decision: Since the p-value is less than 0.05, we reject the null hypothesis.
This data provides sufficient evidence to support the conclusion that the correlation between crime rate and the
proportion of change in household income over the past several years is significant on a level of significance 5%.
Furthermore, the data supports the hypothesis that the proportion of change in household income over the past
several years and crime rate are significantly associated on a level of significance 5%.
i) Interpret the slope for PROP_CHANGE_INCOME if appropriate. If not, argue why.
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