Internet tax: In 2013, a consulting company asked 1037 U.S. adults whether they beleved that people should pay sales tax on items purchased over theinternet. Of these, 446 said they supported such a tax. Does the survey provide convincing evidence that the percentage of U.S. adults who favor an internetsales tax differs from 48%? Use the a -0.05 level of significance and the P value method with the table.Part: 0/5Part 1 of 5State the appropriate null and altermate hypotheses.This hypothenis test is a (Choose one) test.

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Answered: Internet tax: In 2013, a consulting…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Income Tax and the IRS. In 2010, the Internal Revenue Service (IRS) sampled 308,946 tax returns to obtain estimates of various parameters. Data were published in Statistics of Income, Individual Income Tax Returns. According to that document, the mean income tax per return for the returns sampled was $11,266. a. Explain the meaning of sampling error in this context.b. If, in reality, the population mean income tax per return in 2010 was $11,354, how much sampling error was made in estimating that parameter by the sample mean of $11,266?c. If the IRS had sampled 400,000 returns instead of 308,946, would the sampling error necessarily have been smaller? Explain your answer.d. In future surveys, how can the IRS increase the likelihood of small sampling error?
A study compared the felt intensity of unrequited love among three groups - individuals who were currently experiencing unrequited love, those who had previously experienced unrequited love and described their experiences retrospectively, and those who had never experienced unrequited love but described how they thought they would feel if they were to experience it. The results of the study are summarized in the accompanying table. Determine the significance of the difference among groups, using the 5% level. N 40 40 40 M 3.5 3.3 3.7 S2 5.3 5.8 4.8 1. What is th null hyp? 2.The comparison distribution will be an F distribution with df= ? and df=? 3.Determine the cutoff sample score on the comparison distribution at which the null hypothesis should be rejected for the data. At 0.05 the cutoff for F=? 4. Determine the sample's score on the comparison distribution for the data. F=?
Determine if the survey question is biased. If the question is biased, suggest a better wording. How often do you eat vegetables during an average month? Is the question biased? OA. Yes, because it does not lead the respondent to any particular answer. A better question would be "Why is eating vegetables good for you?" OB. Yes, because it influences the respondent into thinking that eating vegetables is good for you. A better question would be "Do you think that eating vegetables is good for you?" OC. No, because it influences the respondent into thinking that eating vegetables is good for you. OD. No, because it does not lead the respondent to any particular answer.
GSS 2018 respondents were asked to rate their level of agreement to the statement, “Differences in income in America are too large.” Responses were measured on a 5-point scale: 1 = strongly agree, 2 = agree, 3 = neutral, 4 = disagree, and 5 = strongly disagree. Strong Democrats had an average score of 1.69 (s = 1.04, N = 86) while strong Republicans had an average score of 2.11 (s = 1.05, N = 67). The estimated standard error of the difference between meansis 0.17. What is the appropriate test statistic? Why? Test the null hypothesis with a one-tailed test (strong Democrats are more likely to agree with the statement than strong Republicans); α = .05. What do you conclude about the difference in attitudes for these two political groups? If you conducted a two-tailed test with α = .05, would your decision have been different?
please do the following parts, this is one question! hypotheses, assumptions, and please check the assumptions (listed as a problem in the image)
A research poll included 1614randomly selected adults who were asked whether "global warming is a problem that requires immediate government action." Results showed that 972 of those surveyed indicated that immediate government action is required. A news reporter wants to determine whether these survey results constitute strong evidence that the majority (more than 50%) of people believe that immediate government action is required. Complete parts (a) through (c) below. a. What is the best estimate of the proportion of adults who believe that immediate government action is required? the best estimate is ?
Question Bias Which of the following survey questions would NOT show bias? Select one: Don't you agree that eating whole grain food improve your O a. health? O b. How much do you exercise during an average week? O c. If someone is distracted by text messaging while they are driving, are they more likely to have an accident? O d. Is outsourcing of jobs to other countries justified if it takes away current jobs from American citizens.
dults aged 18 years old and older were randomly selected for a survey on obesity. Adults are considered obese if their body mass index (BMI) is at least 30. The researchers wanted to determine if the proportion of southern women who are obese is less than the proportion of southern men who are obese. The results are shown in the table below. Test at the 1% level of significance. Number who are obese Sample size Men 42,773 155,525 Women 67,176 248,775 a.State the distribution to use for the test. (Round your answers to five decimal places. b. What is the test statistic c. Conduct a Hypothesis Test
Statistics Canada conducts an annual survey to estimate the proportion of Canadians aged 20 - 24 years of age who are smokers. The most recent application of the Canadian Tobacco Monitoring Survey involved a random sample of n=496 Canadians aged 20 to 24 years of age. Each was asked for the smoking status. The number of 20 to 24 year-olds sampled who indicated they were smokers was 333.(a) Compute the sample proportion. Use at least four decimals in your answer.p^= __________ (b) Using your answer in (a), find a 97% confidence interval for pnow, the current proportion of 20 to 24 year old Canadians who are smokers, by Bootstrapping 1000 samples. Use the seed 3994 to ensure that R-Studio "randomly" samples the same "random" samples as this question will expect.You can do this by including the code, you can copy it into your R-Studio to bootstrap your samples.RNGkind(sample.kind = "Rejection");set.seed(3994);B=do(1000) * mean(resample(c(rep(1,333),rep(0,496-333)), 496));Use at least four…
Quality Progress, February 2005, reports on improvements in customer satisfaction and loyalty made by Bank of America. A key measure of customer satisfaction is the response (on a scale from 1 to 10) to the question: "Considering all the business you do with Bank of America, what is your overall satisfaction with Bank of America?" Here, a response of 9 or 10 represents "customer delight." Suppose that the survey selected 480 customers. Assume that 45% of Bank of America customers would currently express customer delight. That is, assume p= .45. (a) Find the probability that the sample proportion obtained from the sample of 480 Bank of America customers would be within three percentage points of the population proportion. That is, find P(.42 ≤ § ≤ .48). (Round your answer to 4 decimal places. Do not round intermediate values. Round z-value to 2 decimal places.) P(0.42 ≤ (p-hat) ≤ 0.48)

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