Interior and Extertor (3x+2), aveand m4E = Cxt 1B)=

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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### Understanding Interior and Exterior Angles in Triangles

Given a triangle, ΔCOE:

- Let the measure of angle C (m∠C) be expressed as (3x+2) degrees.
- Let the measure of the exterior angle D (m∠D) be expressed as (6x+18) degrees.
- Let the measure of angle E (m∠E) be expressed as (2x+16) degrees.

**Problem: Find m∠D**

To solve for m∠D, we use the property of exterior angles in a triangle, which states that the measure of an exterior angle is equal to the sum of the measures of the two opposite interior angles.

Mathematically, this can be set up as:

\[ m∠D = m∠C + m∠E \]

Substitute the given expressions for the angles:

\[ 6x + 18 = (3x + 2) + (2x + 16) \]

Now, simplify and solve for x:

\[ 6x + 18 = 3x + 2 + 2x + 16 \]
\[ 6x + 18 = 5x + 18 \]
\[ 6x - 5x = 18 - 18 \]
\[ x = 0 \]

Next, substitute x back into the expressions to find each angle's measure:

- For m∠C: \( 3(0) + 2 = 2 \) degrees
- For m∠E: \( 2(0) + 16 = 16 \) degrees
- Verify m∠D: \( 6(0) + 18 = 18 \) degrees

Thus, the measure of angle D (m∠D) is **18 degrees**.
Transcribed Image Text:### Understanding Interior and Exterior Angles in Triangles Given a triangle, ΔCOE: - Let the measure of angle C (m∠C) be expressed as (3x+2) degrees. - Let the measure of the exterior angle D (m∠D) be expressed as (6x+18) degrees. - Let the measure of angle E (m∠E) be expressed as (2x+16) degrees. **Problem: Find m∠D** To solve for m∠D, we use the property of exterior angles in a triangle, which states that the measure of an exterior angle is equal to the sum of the measures of the two opposite interior angles. Mathematically, this can be set up as: \[ m∠D = m∠C + m∠E \] Substitute the given expressions for the angles: \[ 6x + 18 = (3x + 2) + (2x + 16) \] Now, simplify and solve for x: \[ 6x + 18 = 3x + 2 + 2x + 16 \] \[ 6x + 18 = 5x + 18 \] \[ 6x - 5x = 18 - 18 \] \[ x = 0 \] Next, substitute x back into the expressions to find each angle's measure: - For m∠C: \( 3(0) + 2 = 2 \) degrees - For m∠E: \( 2(0) + 16 = 16 \) degrees - Verify m∠D: \( 6(0) + 18 = 18 \) degrees Thus, the measure of angle D (m∠D) is **18 degrees**.
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