Given:```javainterface B{ int a; void methodA();}```Options:- ○ no problem- ○ the method needs to be public- ○ the variable a must be assigned a value- ○ the method needs to have a bodyExplanation:This image presents a Java interface, named `B`, which contains an integer variable `a` and a method signature `void methodA()`. The options below represent possible errors or corrections in the interface's definition. A key point in Java is that interface methods cannot have bodies, and fields must be implicitly public, static, and final, thus needing initialization.The student needs to identify potential issues:- The variable `a` must be initialized.- The method `methodA()` does not need a body as it is in an interface. ### Provided Code Structure**Interface Declaration:**```javainterface B { void methodA();}```An interface `B` is defined with a single method `methodA()`.**Class Implementation:**```javaclass C implements B { void methodA() { } void methodB() { }}```Class `C` implements the interface `B`. It provides implementations for `methodA` and defines an additional method `methodB`.### Conceptual Questions1. **methodA cannot be overridden:** - This option is incorrect because as an abstract method in an interface, `methodA` must be implemented (overridden) in the implementing class `C`.2. **methodB should be overridden:** - This option is misleading. `methodB()` is not part of any interface or superclass in the provided context, so there is nothing to override unless it’s specified elsewhere.3. **methodA should be declared as public in class C:** - This option is correct. Methods in an interface are implicitly public, and when implementing them in a class, they must be declared public.4. **everything is fine:** - This option is incorrect because `methodA` in class `C` is effectively package-private, violating the access level required by the interface implementation. ### ConclusionThe correct choice is that `methodA` should be declared as public in class `C` to correctly implement the interface `B`.

Interface is very similar to an abstract class where it consists of different methods and members…

Answered: interface B int a; void methodA(); O no…

interface B int a; void methodA(); O no problem the method needs to be public the variable a must be assigned a value O the method needs to have a body

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Given:

```java
interface B
{
int a;
void methodA();
}
```

Options:
- ○ no problem
- ○ the method needs to be public
- ○ the variable a must be assigned a value
- ○ the method needs to have a body

Explanation:
This image presents a Java interface, named `B`, which contains an integer variable `a` and a method signature `void methodA()`. The options below represent possible errors or corrections in the interface's definition. A key point in Java is that interface methods cannot have bodies, and fields must be implicitly public, static, and final, thus needing initialization.

The student needs to identify potential issues:
- The variable `a` must be initialized.
- The method `methodA()` does not need a body as it is in an interface.

### Provided Code Structure

**Interface Declaration:**
```java
interface B {
void methodA();
}
```
An interface `B` is defined with a single method `methodA()`.

**Class Implementation:**
```java
class C implements B {
void methodA() { }
void methodB() { }
}
```
Class `C` implements the interface `B`. It provides implementations for `methodA` and defines an additional method `methodB`.

### Conceptual Questions

1. **methodA cannot be overridden:**
- This option is incorrect because as an abstract method in an interface, `methodA` must be implemented (overridden) in the implementing class `C`.

2. **methodB should be overridden:**
- This option is misleading. `methodB()` is not part of any interface or superclass in the provided context, so there is nothing to override unless it’s specified elsewhere.

3. **methodA should be declared as public in class C:**
- This option is correct. Methods in an interface are implicitly public, and when implementing them in a class, they must be declared public.

4. **everything is fine:**
- This option is incorrect because `methodA` in class `C` is effectively package-private, violating the access level required by the interface implementation.

### Conclusion

The correct choice is that `methodA` should be declared as public in class `C` to correctly implement the interface `B`.

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