Interactive LearningWare 28.10 reviews the concepts that play roles in this problem. The distance from earth to the center of our galaxy is about 30,000 ly (1 ly = 1 light year = 9.47 × 1015 m), as measured by an earth-based observer. A spaceship is to make this journey at a speed of 0.9990c. According to a clock on board the spaceship, how long will it take to make the trip? Express your answer in years. (1 yr is equal to 3.16 × 107 s.)

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Interactive LearningWare 28.10 reviews the concepts that play roles in this problem. The distance from earth to the center of our galaxy is about 30,000 ly (1 ly = 1 light year = 9.47 × 1015 m), as measured by an earth-based observer. A spaceship is to make this journey at a speed of 0.9990c. According to a clock on board the spaceship, how long will it take to make the trip? Express your answer in years. (1 yr is equal to 3.16 × 107 s.)

A spaceship travels at a constant speed from earth to a planet orbiting another star. When the spacecraft arrives, 11
years have elapsed on earth, and 9.6 years have elapsed on board the ship. How far away (in meters) is the planet,
according to observers on earth?
Earth
Ship
Earth
Ship
time
time
time
time
Spaceship departs earth
Spaceship arrives at distant planet
Transcribed Image Text:A spaceship travels at a constant speed from earth to a planet orbiting another star. When the spacecraft arrives, 11 years have elapsed on earth, and 9.6 years have elapsed on board the ship. How far away (in meters) is the planet, according to observers on earth? Earth Ship Earth Ship time time time time Spaceship departs earth Spaceship arrives at distant planet
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