Integrating with repeated linear factors Evaluate f (x) dr, where 5x² – 3x + 2 f(x) x – 2x?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Integrating with repeated linear factors Evaluate f (x) dr, where
5x² – 3x + 2
f(x)
x – 2x?
Transcribed Image Text:Integrating with repeated linear factors Evaluate f (x) dr, where 5x² – 3x + 2 f(x) x – 2x?
Expert Solution
Step 1: Given

f(x)=5x2-3x+2x3-2x2

 

To find:

f(x) dx [By partial fractions]

Step 2:

A rational function f(x) is a ratio of two polynomials p(x)q(x), where q(x) ≠ 0.

If the degree of p(x) is lesser than the degree of q(x), then it is a proper fraction, else it is an improper fraction. 

 

The process of taking a rational expression (improper fraction) and decomposing it into simpler rational expressions that we can add or subtract to get the original rational expression is called partial fraction decomposition.

For each factor in the q(x) we can use the following table to determine the term(s) we pick up in the partial fraction decomposition.

Factor in denominator Term in partial fraction decomposition
Calculus homework question answer, step 2, image 1 Calculus homework question answer, step 2, image 2
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Calculus homework question answer, step 2, image 7 Calculus homework question answer, step 2, image 8

 

Step 3

f(x)=5x2-3x+2x3-2x2 is a improper fraction.

f(x)=5x2-3x+2x3-2x2=5x2-3x+2x2(x-2)

We can decompose it as

5x2-3x+2x2(x-2)=Ax+Bx2+C(x-2)5x2-3x+2x2(x-2)=Ax×x(x-2)x(x-2)+Bx2×(x-2)(x-2)+C(x-2)×x2x2=Ax(x-2)x2(x-2)+B(x-2)x2(x-2)+Cx2x2(x-2)5x2-3x+2x2(x-2)=Ax(x-2)+B(x-2)+Cx2x2(x-2)5x2-3x+2=Ax(x-2)+B(x-2)+Cx2                         ...(1)

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