Stuck need help!The class I'm taking is computer science discrete structures. Problem is attached. please view attachment before answering. Really struggling with this concept. Thank you so much. Suppose a password protection protocol requires the use of three unique positiveintegers followed by a string of six lowercase characters. The characters may be reusedbut the integers may not.a) How many such passwords are possible?b) If you are trying to guess a password with this scheme and you know that thepassword has '123' as its unique integers, what is the probability you guess thepassword on the first try?c) If you know that the password contains 123 as its unique integers and contains theletter 'a' somewhere, what is the probability you guess the password on the firsttry?

Q: Answer the given questions based on the statementA: 1. Total possible passwords = 10*9*8*26*26*26*26*26*26 -> 222419358720 possible passwords 10 unique integer options for first place 9 unique integer options for second place (excluding the first one) 8 unique integer options for first place (excluding the previous ones) 26 character options for next 6 places (since they are repeatable) 2. Probability of guessing correct password provided 3 integers are 123 -> 1/26*1/26*1/26*1/26*1/26*1/26 = 1/308915776 Since the probability of correctly guessing correct character is 1/26, which is then repeated 6 times. 3. Probability of guessing password provided integers are 123 and 'a' is in the password. NOTE: I AM ASSUMING THE 'a' CHARACTER OCCURS ONLY ONCE SINCE IT IS NOT MENTIONED IN THE QUESTION. Probability = 1/6*1/25*1/25*1/25*1/25*1/25 = 1/58593750 1/6 -> probability of guessing correct position of 'a' 1/25 -> probability of guessing correct alphabet excluding a