inte b-a [*1 (x) dx f (x) dx = limf (x;) A.x, where Ax = Δ., 71-00 Use the given form of the definition to evaluate the integral. n
inte b-a [*1 (x) dx f (x) dx = limf (x;) A.x, where Ax = Δ., 71-00 Use the given form of the definition to evaluate the integral. n
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
5.2 q9
![Tutorial Exercise
If f is integrable on [a, b], the following equation is correct.
[²ƒ (x) dx =
=
Part 1 of 6
Part 2 of 6
i=1
Use the given form of the definition to evaluate the integral.
La
Part 3 of 6
Using
6i
If Xo = -2, then each x; = −2+ iAx = -2 +
lim
72-00
Since the interval is [-2, 4] and we have n sub-intervals, then Ax =
Part 4 of 6
(1 + 5x) dx
n
Now, lim
72
i=1
lim Ĺ (1 + 5(-2 + 6i)) 6 =
Σ
77-00
i = 1
4
12 (1 + 5x) dx = lim (1 + 5x;) Ax, we have
n→∞o
f (xi) Ax, where A.x =
n-coin
Σ=1
i = 1
n
6
- -º- (-9 + 301) =
n
i = 1
X
n
· = lim £Σ (Ε
n
6
= lim
n→∞ n
Submit Skip (you cannot come back)
^6-3
i = 1
i=1
-9 +
b- a
n
n
n
6i
and x₂ =
+
30i
But
M³
= a +iAx.
n
n
30i
-9 = 36
6
X
"
and](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F051a995a-b9bf-4344-83a2-dd4555fc9989%2F6ffc9f71-a97a-4e91-9c66-02b24fa3a4d3%2Fiewufmv_processed.png&w=3840&q=75)
Transcribed Image Text:Tutorial Exercise
If f is integrable on [a, b], the following equation is correct.
[²ƒ (x) dx =
=
Part 1 of 6
Part 2 of 6
i=1
Use the given form of the definition to evaluate the integral.
La
Part 3 of 6
Using
6i
If Xo = -2, then each x; = −2+ iAx = -2 +
lim
72-00
Since the interval is [-2, 4] and we have n sub-intervals, then Ax =
Part 4 of 6
(1 + 5x) dx
n
Now, lim
72
i=1
lim Ĺ (1 + 5(-2 + 6i)) 6 =
Σ
77-00
i = 1
4
12 (1 + 5x) dx = lim (1 + 5x;) Ax, we have
n→∞o
f (xi) Ax, where A.x =
n-coin
Σ=1
i = 1
n
6
- -º- (-9 + 301) =
n
i = 1
X
n
· = lim £Σ (Ε
n
6
= lim
n→∞ n
Submit Skip (you cannot come back)
^6-3
i = 1
i=1
-9 +
b- a
n
n
n
6i
and x₂ =
+
30i
But
M³
= a +iAx.
n
n
30i
-9 = 36
6
X
"
and
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