What would be printed from the following program when run using 2 4 as data?int s(int x, int y):int main()int a, b̟c;scanf(“%d °od",&a,&b):c = s(a,b);printf("%d",c);return 0;}int s (int x, int y)return (x+y)%x;Previous0 000

The Answer for the c program is

Answered: int s(int x, int y): int main() int a,…

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter6: Modularity Using Functions

Section6.4: A Case Study: Rectangular To Polar Coordinate Conversion

Problem 9E: (Numerical) Write a program that tests the effectiveness of the rand() library function. Start by...

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Rewrite the program with a little bit of changes in the codes
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What does the function return for any positive values of x and n ? The answer should be a general formula in terms of x and n. int what_do_I_do ( int x, int n ) { if ( n = = 1 ) return x; else return x + what_do_I_do ( x, n – 1 ); } C++ be quick please
using c++, create a program with this expected output: Enter the number of rows and columns: 3 4 Enter 4 number(s) for row number 0: 1 2 3 4 Enter 4 number(s) for row number 1: 5 6 7 8 Enter 4 number(s) for row number 2: 9 10 11 12 Board: 1 2 3 4 5 6 7 8 9 10 11 12 note: use these methods: void fill(int **p, int rowSize, int columnSize); void print(int **p, int rowSize, int columnSize);
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You can find out how many seconds have elapsed since Jan 1, 1970 using the time() function. #include <time.h> now = time(NULL); // now is more than a billion seconds (which data type should you use?) Write a program that estimates how many years, months, weeks, days, and hours have gone by since Jan 1 1970 by calculations with the number of seconds that have passed. The number of months must be less than 12, i.e., take out how many years have gone by first, then how many months are left, then weeks, etc. Assume that all years have 365 days, and all months have 30.42 days. Don’t use a calculator, or any web site that reports the number of seconds in a month, etc. – your C program can calculate anything that you need. Notice that this is an assignment on using arithmetic in C. Hints. How many seconds are in a minute? hour? A day? A week? A month? A year?
Suppose you want to deposit a certain amount of money into a savings account, and thenleave it alone to draw interest for the next 10 years. At the end of 10 years, you would like tohave $10,000 in the account. How much do you need to deposit today to make that happen?You can use the following formula, which is known as the present value formula, to find out:The terms in the formula are as follows: [5 marks]• P is the present value, or the amount that you need to deposit today.• F is the future value that you want in the account. (In this case, F is $10,000.)• r is the annual interest rate.• n is the number of years that you plan to let the money sit in the account.Write a method named presentValue that performs this calculation. The method should accept the future value, annual interest rate, and number of years asarguments. It should return the present value, which is the amount that you need to deposit today.Demonstrate the method in a program that lets the user experiment with…
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C++ - When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This can be done by normalizing to values between 0 and 1, or throwing away outliers. For this program, adjust the values by subtracting the smallest value from all the values. The input begins with an integer indicating the number of integers that follow. Ex: If the input is: 5 30 50 10 70 65 the output is: 20 40 0 60 55 The 5 indicates that there are five values in the list, namely 30, 50, 10, 70, and 65. 10 is the smallest value in the list, so is subtracted from each value in the list. For coding simplicity, follow every output value by a space, including the last one.
Rewrite the program with a little bit of changes in the codes
The correct statements are: (ab)*a = a(ba)* (a U b)* b (a U b)* = a*b (a U b)* (a U b)* ba (a U b)* U a*b* = (a U b)* □ (a U b)* b (a U b)* U (a U b)* a (a U b)* = (a U b)*

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int s(int x, int y): int main() int a, b̟c; scanf(*%d %d",&a,&b); c = s(a,b); printf("%d",c); return 0; int s (int x, int y) return (x+y)%x;