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int main() { int *aptr; int *bptr, int *cptr; int valuel = 0; int value2 = 0; int result = 0; aptr = &value1; bptr = &value2; *bptr = value2 + 5; *aptr = 6; cptr = &value2; *cptr = *aptr + *bptr; result = value1+value2; printf(“%d",result); return 0;

int main() { int *aptr; int *bptr, int *cptr; int valuel = 0; int value2 = 0; int result = 0; aptr = &value1; bptr = &value2; *bptr = value2 + 5; *aptr = 6; cptr = &value2; *cptr = *aptr + *bptr; result = value1+value2; printf(“%d",result); return 0;

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Determine the output of following program: int main() { int *aptr. int *bptr; int *cptr; int valuel = 0; int value2 = 0; int result = 0; aptr = &value1; bptr = &value2; *bptr = value2 + 5; *aptr = 6; cptr = &value2; *cptr = *aptr + *bptr; result = value1+value2; printf(“%d",result): return 0;
Transcribed Image Text:Determine the output of following program: int main() { int *aptr. int *bptr; int *cptr; int valuel = 0; int value2 = 0; int result = 0; aptr = &value1; bptr = &value2; *bptr = value2 + 5; *aptr = 6; cptr = &value2; *cptr = *aptr + *bptr; result = value1+value2; printf(“%d",result): return 0;
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