int a[10]; char * s = "hello"; int f(int i, int b[]) { int j=i; A:{ int i=j; char c = b[i]; // ...; } return 0; } void g(char * s) { char c = s [ 0]; B:{ int a[5];: // ...; } } main () { int x=1; x = f(x,a); g(s); return 0; }
int a[10]; char * s = "hello"; int f(int i, int b[]) { int j=i; A:{ int i=j; char c = b[i]; // ...; } return 0; } void g(char * s) { char c = s [ 0]; B:{ int a[5];: // ...; } } main () { int x=1; x = f(x,a); g(s); return 0; }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
100%
(Run-time environment) Draw a possible organization for the runtime environment of the following C
1. after entry into block A in function f.
2. after entry into block B in function g.
PLEASE SHOW IT CLEARLY WITH THE EXPLANATION.
THANK YOU.
Transcribed Image Text:X: 15
Y: 10
Globalstatic area
Activation record of
main
u: 15
V: 10
control link
return address
Activation record of
first call to gcd
u: 10
V: 5
- control link
Activation record of
second call to gcd
return address
u: 5
V: 0
Activation record of
control link
return address
third call to gcd
Direction of
stack growth
![int a[10];
2 || char * s = " hello";
1
3
|int f(int i, int b[])
5|{ int j=i;
A:{ int i=j ;
char c = b[i];
// ...;
}
return 0;
4
6
8
10
}
11
12
13 void g(char * s)
{ char c = s [0];
B:{ int a[5];
// ...;
}
14
15
16
17
18 }
19
main ()
{ int x=1;
x = f(x, a);
g(s);
return 0;
20
21
22
23
24
}
25](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fceb76ecc-c617-4dcc-8586-e89b08b5b658%2Fe928acaf-df41-404d-80b1-23e8e1f4f95a%2Fnbbtnx_processed.png&w=3840&q=75)
Transcribed Image Text:int a[10];
2 || char * s = " hello";
1
3
|int f(int i, int b[])
5|{ int j=i;
A:{ int i=j ;
char c = b[i];
// ...;
}
return 0;
4
6
8
10
}
11
12
13 void g(char * s)
{ char c = s [0];
B:{ int a[5];
// ...;
}
14
15
16
17
18 }
19
main ()
{ int x=1;
x = f(x, a);
g(s);
return 0;
20
21
22
23
24
}
25
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