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Instructor Problem 3: Matlab provided the following answers: a) √j = 0.707 + j0.707 b) √−j = 0.707 - j0.707 c) (√) ¹ = 0.4599+j0 d) cos(j) = 1.5431 e) sin(j) = 0 + j1.1752 For each part using your knowledge of Euler's equation and complex numbers verify that the answers are correct.

Instructor Problem 3: Matlab provided the following answers: a) √j = 0.707 + j0.707 b) √−j = 0.707 - j0.707 c) (√) ¹ = 0.4599+j0 d) cos(j) = 1.5431 e) sin(j) = 0 + j1.1752 For each part using your knowledge of Euler's equation and complex numbers verify that the answers are correct.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Instructor Problem 3: Matlab provided the following answers: a) √j = 0.707 + j0.707 b) √−j = 0.707 - j0.707 c) (√) ¹ = 0.4599+j0 d) cos(j) = 1.5431 e) sin(j) = 0 + j1.1752 For each part using your knowledge of Euler's equation and complex numbers verify that the answers are correct.
Transcribed Image Text:Instructor Problem 3: Matlab provided the following answers: a) √j = 0.707 + j0.707 b) √−j = 0.707 - j0.707 c) (√) ¹ = 0.4599+j0 d) cos(j) = 1.5431 e) sin(j) = 0 + j1.1752 For each part using your knowledge of Euler's equation and complex numbers verify that the answers are correct.
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